All categories

3 years ago

I have a density of 1.61g/cm^3 and a mass of 28g. Find the missing value

Physics

1 answer:

Tamiku [17]3 years ago

8 0

The missing value is the 'k' that should appear between '28' and 'g' .

Nobody has a mass of 28g.

My new grandson, who was born yesterday (January 29, 2019), had a mass of 4,039g at birth.

Mother and son are happy and resting comfortably today, in Kfar Tapuach, Samaria, Israel.

You might be interested in

· A car moves at 12 m/s and coasts up a hill with a

Zigmanuir [339]

Explanation:

Given that,

Initial speed of a car, u = 12 m/s

Aceleration, a = -1.6 m/s²

(a) The displacement of car after 6 seconds is :

$d=ut+\dfrac{1}{2}at^2\\\\d=12\times 6+\dfrac{1}{2}\times (-1.6)\times 6^2\\\\d=43.2\ m$

(b) The displacement of the car after 9 seconds is :

$d=ut+\dfrac{1}{2}at^2\\\\d=12\times 9+\dfrac{1}{2}\times (-1.6)\times 9^2\\\\d=43.2\ m$

Hence, this is the required solution.

7 0

3 years ago

What is the S.I. unit of drift velocity and electron mobility?

Degger [83]

<span>We use m/s for the velocity, and m2/(V·s) for the </span><span>mobility.</span>

7 0

3 years ago

When to objects stick together the mass of the combined object is equal to the

Natasha2012 [34]

Answer: Masses of the two objects added together

Explanation:

7 0

3 years ago

To haul a boat out of the water for the winter, a worker at the storage facility uses a wide strap with cables operating at the

Masteriza [31]

Answer:

Tension in each cable is 3474 N when angle made by the string with horizontal 46 degree

Tension in each cable is 4852 N when angle made by the string with horizontal 31 degree

Explanation:

In this problem, for the boat to be at rest then tension in the strings must be such that the horizontal components balance each other and the vertical components balance weight of the boat.

Consider horizontal components for equilibrium

If the angle made by the string with horizontal 46 degree

$T_{1} cos\theta=T_{2} cos\theta\\T_{1}=T_{2$

Tension the each string is same

Consider vertical components for equilibrium

$T_{1} sin\theta+T_{2} sin\theta=mg\\\\T_{1} sin46+T_{2} sin46=510 \times 9.8\\\\2T_{1}sin46=4998............(here T_{1}=T_{2})\\T_{1}=3474.01 N$

Tension in each cable is 3474 N when angle made by the string with horizontal 46 degree

If the angle made by the string with horizontal 31 degree, then

$T_{1} sin\theta+T_{2} sin\theta=mg\\\\T_{1} sin31+T_{2} sin31=510 \times 9.8\\\\2T_{1}sin31=4998............(here T_{1}=T_{2})\\T_{1}=4852.06 N$

Tension in each cable is 4852 N when angle made by the string with horizontal 31 degree

6 0

3 years ago

The Flintstones and Rubbles decide to try out the new inclined bowling alley, ``Bedslant Bowling''. Betty's ball and Wilma's bal

bogdanovich [222]

Explanation:

fred ball hit the pin the time for all just put a hit in his right knee and do not need to be on bed at the carbon footprint in his first year of practice at all but his teammates were also on bed and you were a good friend to be with you cute guys that he is the most likely and do you have the ability for you I don't want him on you and

5 0

3 years ago