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3 years ago

15

A 150-kg object takes 1.5 minutes to travel a 2,500-meter straight path. It begins the trip traveling 120 m/s and decelerates to

a velocity of 20 m/s. What was its acceleration?

2 answers:

podryga [215]3 years ago

7 0

I believe it is -1.11 m/s^2. I will let you know if its correct

Rom4ik [11]3 years ago

5 0

Your answer is -1.11m/s2. i know this cause i had it right on a test. hope this helps everyone else looking for the answer

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2 years ago

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A scientist spends most of her time observing the motion of objects and how they behave. Which branch of science is she most lik

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2 years ago

At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light to 1515

Talja [164]

Complete Question

At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light to 1/5.

Answer:

The angle is

Explanation:

From the question we are told that

The light emerging from second Polaroid is 1/5 the unpolarized

Generally the intensity of light emerging from the first Polaroid is mathematically represented as

$I_1 = \frac{I_o}{ 2 }$

Generally from the Malus law the intensity of light emerging from the second Polaroid is mathematically represented

$I_2 = I_1 cos^2 (\theta )$

=> $cos^2 (\theta ) = \frac{I_2}{I_1 }$

=> $cos (\theta) = \sqrt{ \frac{I_2}{I_1} }$

From the question $I_2 = \frac{I_o}{5}$

$cos (\theta) = \sqrt{ \frac{ \frac{ I_o}{5} }{\frac{I_o}{2} } }$

$cos (\theta) = \sqrt{ \frac{2}{5} }$

=> $\theta = cos ^{-1} [\sqrt{\frac{2}{5}} ]$

=> $\theta = 50.77^o$

8 0

3 years ago