Answer:
a) the magnitude of the force is
F= Q(
) and where k = 1/4πε₀
F = Qqs/4πε₀r³
b) the magnitude of the torque on the dipole
τ = Qqs/4πε₀r²
Explanation:
from coulomb's law
E = 
where k = 1/4πε₀
the expression of the electric field due to dipole at a distance r is
E(r) =
, where p = q × s
E(r) =
where r>>s
a) find the magnitude of force due to the dipole
F=QE
F= Q(
)
where k = 1/4πε₀
F = Qqs/4πε₀r³
b) b) magnitude of the torque(τ) on the dipole is dependent on the perpendicular forces
τ = F sinθ × s
θ = 90°
note: sin90° = 1
τ = F × r
recall F = Qqs/4πε₀r³
∴ τ = (Qqs/4πε₀r³) × r
τ = Qqs/4πε₀r²
<span>Power is measured in watts. A watt is the power that it takes to do one joule ofwork in one second. It can be found using the formula <span>P=<span>Wt</span></span>. (In this formula, W stands for "work.")</span><span><span>Large amounts of energy can be measured in kilowatts (<span>1kW=1×<span>103</span>W</span>), megawatts (<span>1MW=1×<span>106</span>W</span>), or gigawatts (<span>1GW=1×<span>109</span>W</span>).</span><span><span> This is helpful</span><span> This is confusing</span></span></span><span>The watt is named James Watt, who invented an older unit of power: the horsepower.</span>
Answer:
147.7 N
221.55 Nm
Explanation:
P = Pressure = 100000 Pa
= Mass-specific gas constant = 287.015 J/kg k
T = Temperature = 10+273 = 283 K
C = Drag coefficient = 1.1
A = Area
r = Radius = 0.2 m
v = Speed of wind = 
L = Length of pole
Density

Drag force

Force on the circular sign is 147.7 N

Bending moment at the bottom of the pole is 221.55 Nm
Personally, I agree with your answer, namely that the likely-intended event happening here is one of acceleration. Having said that, I also want to add: it pains me to see this type of wording because, clearly, it is vague and only invites confusion of the type you are talking about.
Good luck!
Answer:
481.76 J/mol
133.33 K
Explanation:
= Avogadro's number = 
Change in enthalpy is given by

Entropy is given by

Latent heat of fusion is given by

The latent heat of fusion is 481.76 J/mol
Melting point is given by

Melting occurs at 133.33 K