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4 years ago

a Ferrari with an initial velocity of 10 m/s, comes to a complete stop in 5 seconds, what will its acceleration be?

Physics

2 answers:

Aleks04 [339]4 years ago

8 0

Acceleration = (change in speed) / (time for the change)

Change in speed = (speed at the end) minus (speed at the beginning)

Change in speed = (zero) minus (10 m/s) = negative 10 m/s

Acceleration = (-10 m/s) / (5 sec)

Acceleration of the Ferrari = -2 m/s²

Democratically, it doesn't have to be a Ferrari. If my 16-yr-old Dodge is going 10 m/s and stops in 5 sec, its acceleration would be the same number.

11111nata11111 [884]4 years ago

6 0

10 m/s divided by 5 s

-2m/s/s

minus - deceleration

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3 years ago

A rocket moves upward from rest with an acceleration of 40 m/s2 for 5 seconds. It then runs out of fuel and continues to move up

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Answer:

Maximum height of rocket = 2538.74 m

Explanation:

We have equation of motion s = ut + 0.5 at²

For first 5 seconds

s = 0 x 5 + 0.5 x 40 x 5² = 500 m

Now let us find out time after 5 seconds rocket move upward.

We have the equation of motion v = u + at

After 5 seconds velocity of rocket

v = 0 + 40 x 5 = 200 m/s

After 5 seconds the velocity reduces 9.8m/s per second due to gravity.

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$t=\frac{200}{9.81}=20.38s$

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3 years ago

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3 years ago

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3 years ago

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Answer:

The fall in temperature of the liquid is 8.6 +/- 0.1 ⁰C

Explanation:

Given;

initial temperature of the liquid, t₁ = 76.3 +/- 0.4⁰C

final temperature of the liquid, t₂ = 67.7 +/- 0.3⁰C

The change in temperature of the liquid is calculated as;

Δt = t₂ - t₁

Δt = (67.7 - 76.3) +/- (0.3 - 0.4)

Δt = (-8.6) +/- (-0.1)

Δt = 8.6 +/- 0.1 ⁰C

Therefore, the fall in temperature of the liquid is 8.6 +/- 0.1 ⁰C

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3 years ago