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DerKrebs [107]
3 years ago
13

(a) The average mpg rating for an older model of a car is 24.8 miles to the gallon and it takes 6.60 x 10^5 J of work done on th

e car to drive one mile. Given that a gallon of gasoline gives 1.19 x 10^8 J of internal energy to the car, what is the amount of heat released to the atmosphere for each mile you drive the car?
Physics
1 answer:
Margarita [4]3 years ago
6 0

Answer:

the gasoline releases Q=-4138387 J/mile to the atmosphere

Explanation:

from the fist law of thermodynamics

ΔU = Q - W

where ΔU= change in internal energy , Q= heat received , W= work done by the system

then

Q = ΔU + W

knowing that

ΔU = internal energy per gallon * number of gallons consumed in 24.8 miles

= (-1.19 x 10^8 J/ gallon) * 1 gallon /24.8 miles = (-4798387 J/mile)

W = work done by mile= 6.60 x 10^5 J/mile

therefore the heat released per mile

Q = ΔU + W = -4798387 J/mile + 6.60 x 10^5 J/mile = -4138387 J

since Q is negative , energy is released into the atmosphere

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Answer:

a) 90 N

Explanation:

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It is represented mathematically as

F = 1/4πε₀(q₁q₂)/d²......................... Equation 1

Where F = Electrostatic force, q₁ = charge on the first metal sphere, q₂ = charge on the second metal sphere, d = distance between the spheres, 1/4πε₀ = proportionality constant.

<em>Given: q₁ = +2.0×10⁻⁵ C, q₂ = 2.0×10⁻⁵, d = 2.0×10⁻¹ m</em>

<em>Constant : 1/4πε₀ = 9×10⁹Nm²/C²</em>

<em>Substituting these values into equation 1,</em>

<em>F = (9×10⁹×2.0×10⁻⁵×2.0×10⁻⁵)/(2.0×10⁻¹)²</em>

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<em>F = 90 N</em>

Therefore the electrostatic force is = 90 N

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Answer:

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