Answer:
172.23L
Explanation:
Data obtained from the question include:
V1 (initial volume) = 200 L
P1 (initial pressure) = 0.94 atm
T1 (initial temperature) = 25°C = 25 + 273 = 298K
P2 (final pressure) = 1atm
T2 (final temperature) = 0°C = 0 + 273 = 273K
V2 (final volume) =?
Using the general gas equation P1V1/T1 = P2V2/T2, the final volume of the container can be obtain as follow:
P1V1/T1 = P2V2/T2
0.94 x 200/298 = 1 x V2/273
Cross multiply to express in linear form as shown below:
298 x V2 = 0.94 x 200 x 273
Divide both side by 298
V2 = (0.94 x 200 x 273)/298
V2 = 172.23L
The new volume of the container is 172.23L
