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slavikrds [6]
3 years ago
7

Helpppp Plsssss Asap!!

Chemistry
1 answer:
Reika [66]3 years ago
8 0

Carbon dioxide scrubber. A carbon dioxide scrubber is a piece of equipment that absorbs carbon dioxide (CO2). It is used to treat exhaust gases from industrial plants or from exhaled air in life support systems such as rebreathers or in spacecraft, submersible craft or airtight chambers.

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ASAP I AM GIVING BRAINLIEST PLEASEEEEEEEEEEEEEEE HELPPPPPPPPPP
faust18 [17]

Answer:

D) It has a different unit than atomic mass.

4 0
3 years ago
If no carbon dioxide is present in your test tube it will be a ____________ color. If a medium amount of CO2 is present, your te
Sloan [31]

if there is no carbon dioxide your test tube will be blue

if there is a medium amount of carbon dioxide your test tube is green

if there are high amounts of CO2 it will be

yellow

7 0
3 years ago
Draw the product of the reaction between CH3CH=CHCH3 and H2 under a platinum catalyst.
Pani-rosa [81]

Answer:

CH₃CH₂-CH₂CH₃

Explanation:

When an alkene, R-CH=CH-R reacts with H₂ in a Pt catalyst, the analogue alkane, R-CH₂-CH₂-R, is produced (Hydrogenation of alkenes via Pt/Pd catalyst)

Thus, the reaction of CH₃CH=CHCH₃ with H₂ under a platinum catalyst produce:

<h3>CH₃CH₂-CH₂CH₃</h3>

The analogue alkane

4 0
3 years ago
Calculate the molecular weight of chalk.write any two advantages of mandeleev's periodic table?
Debora [2.8K]
Part (a):
Chalk has the chemical formula: CaCo₃
From the periodic table:
mass of Ca = 40 grams
mass of Co = 58.9 grams
Therefore:
molecular weight of chalk = 40 + 3(58.9) = 216.7 grams

Part (b):
Advantages of M<span>andeleev's periodic table:
1- Could predict the properties of elements easily based on its position in the periodic table
2- Elements were arranged systematically in order of increasing atomic mass which helped in the study and classification of elements
3- Even after the discovery of noble gases, no major changes needed to be done to the periodic table. Noble gases were inserted easily
4- He left room for other undiscovered elements based on his systematic approach in writing the table

Hope this helps :)</span>
5 0
3 years ago
What is the activity of a 52.3 μCi sample of carbon‑14 in becquerels?
Llana [10]

Answer:

1935100 Bq

Explanation:

Let us recall that:

If 1 μCi can be equivalent to 37000 Bq

Then; the activity of 52.3 μCi will be:

\dfrac{37000 \ Bq}{1 \ \mu Ci}\times 52.3 \ \mu Ci  \\ \\  \\ \\ \mathbf{= 1935100 \ Bq}

3 0
3 years ago
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