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marshall27 [118]
3 years ago
14

What is the activity of a 52.3 μCi sample of carbon‑14 in becquerels?

Chemistry
1 answer:
Llana [10]3 years ago
3 0

Answer:

1935100 Bq

Explanation:

Let us recall that:

If 1 μCi can be equivalent to 37000 Bq

Then; the activity of 52.3 μCi will be:

\dfrac{37000 \ Bq}{1 \ \mu Ci}\times 52.3 \ \mu Ci  \\ \\  \\ \\ \mathbf{= 1935100 \ Bq}

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The wavelength of transmission is 9.7mm. What is the energy of this transition
Sonja [21]

Answer:

E = 2.05×10⁻²³ J

Explanation:

Given data:

Wavelength of transmission = 9.7 mm (9.7/1000 = 0.0097 m)

Energy of transition = ?

Solution:

9.7 mm (9.7/1000 = 0.0097 m)

9.7×10⁻³ m

Formula:

E = hc/λ

By putting values,

E = 6.63 ×10⁻³⁴ Js × 3×10⁸ m/s / 9.7×10⁻³ m

E = 19.89×10⁻²⁶ J.m / 9.7×10⁻³ m

E = 2.05×10⁻²³ J

3 0
3 years ago
What is not a way that a mineral can be formed
Yuri [45]
<span> under extreme heat or pressure
 crystallize from magma
 precipitate from a solution reaction of hot mixture with water and a dissolved substance</span>
8 0
3 years ago
Condensed structural formula of benzoic acid
Deffense [45]
Hmmm I’m not sure just to to quizlet for now but that seems kinda like science and elements
5 0
2 years ago
A 4.86-gram sample of calcium reacted completely with oxygen to form 6.80 grams of calcium oxide. This reaction is represented b
sesenic [268]
The number of mole of Ca reacted is:
4.86 g Ca/ (40.08 g/mol Ca)= 0.121 mol Ca

Because Ca reacted completely with oxygen and there is 2 mol Ca, there is 1 mol O2 reacted.

Total mass of oxygen that reacted is:
0.121 mol Ca* (1mol O2/ 2 mol Ca)* (32 g O2/ 1 mol O2)= 1.94 g O2 reacted.

Hope this would help~
8 0
3 years ago
The monomer of poly(vinyl chloride) has the formula C2H3Cl. If there are 1,565 repeat units in a single chain of the polymer, wh
monitta

Answer:

\large \boxed{9.780 \times 10^{4}\text{ u}}

Explanation:

The molecular mass of a monomer unit is:

C₂H₃Cl = 2×12.01 + 3×1.008 + 35.45 = 24.02 + 3.024 + 35.45 = 62.494 u

For 1565 units,

\text{Molecular mass} = \text{1565 units} \times \dfrac{\text{62.494 u}}{\text{1 unit }} = \mathbf{9.780 \times 10^{4}}\textbf{ u}\\\\\text{The molecular mass of the chain is $\large \boxed{\mathbf{9.780 \times 10^{4}}\textbf{ u}}$}

8 0
3 years ago
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