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marshall27 [118]
3 years ago
14

What is the activity of a 52.3 μCi sample of carbon‑14 in becquerels?

Chemistry
1 answer:
Llana [10]3 years ago
3 0

Answer:

1935100 Bq

Explanation:

Let us recall that:

If 1 μCi can be equivalent to 37000 Bq

Then; the activity of 52.3 μCi will be:

\dfrac{37000 \ Bq}{1 \ \mu Ci}\times 52.3 \ \mu Ci  \\ \\  \\ \\ \mathbf{= 1935100 \ Bq}

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Fantom [35]

Answer:

-33% yield

Explanation:

6 0
3 years ago
When 16.9 g KOH is dissolved in 90.8 g of water in a coffee-cup calorimeter, the temperature rises from 18.5 °C to 34.27 °C. Wha
juin [17]

Answer:

-431.5 J/g

Explanation:

Mass of solution = Mass of solute + mass of solvent

Solute is KOH while solvent is water.

Mass of KOH = 16.9 g

Mass of water = 90.8 g

Mass of solution = 16.9 + 90.8

                          = 107.7 g

Change in temperature (Δt) = 34.27 - 18.5

                                           = 16.2 °C

Heat required to raise the temperature of water is released by dissolving KOH.

Therefore,

Heat released by KOH = m × s× Δt

                                    = 107.7 × 4.18 × 16.2

                                    = 7293 J

Heat released by per g KOH = 7293 J/16.9 g

                                             = 431.5 J/g

As heat is released therefore, enthalpy change would be negative.

Enthalpy change of KOH = -431.5 J/g

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