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SCORPION-xisa [38]
3 years ago
6

Phosphorus pentachloride decomposes to phosphorus trichloride at high temperatures according to the equation:

Chemistry
1 answer:
weqwewe [10]3 years ago
7 0

Answer:

D) [PCl5]=0.00765M,[PCl3]=0.117M,and [Cl2]=0.0.117M

Explanation:

Based on the reaction:

PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)

And knowing:

Kc = [PCl₃] [Cl₂] / [PCl₅] = 1.80

When you add PCl₅ into a flask, this gas will react producing PCl₃ and Cl₂ until [PCl₃] [Cl₂] / [PCl₅] = 1.80

This could be written as:

[PCl₃] = X

[Cl₂] = X

[PCl₅] = 0.125M - X

<em>Where X represents the moles of PCl₅ that react, </em><em>reaction coordinate.</em>

Replacing in Kc expression:

[PCl₃] [Cl₂] / [PCl₅] = 1.80

[X [X] / [0.125 - X] = 1.80

X² = 0.225 - 1.80X

0 = -X² -1.80X + 0.225

Solving for X:

X = -1.9M → False solution, there is no negative concentrations

X = 0.11735M → Right solution.

Replacing, concentrations in equilibrium are:

[PCl₃] = X

[Cl₂] = X

[PCl₅] = 0.125M - X

[PCl₃] = 0.117M

[Cl₂] = 0.117M

[PCl₅] = 0.00765M

And right option is:

<h3>D) [PCl5]=0.00765M,[PCl3]=0.117M,and [Cl2]=0.0.117M</h3>
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4.28 x 10^24 molecules of chlorine gas to moles of chlorine gas.​
mamaluj [8]

Answer:

7.1 moles Cl₂

Explanation:

To solve this problem we will use <em>Avogadro's number </em>(Aₙ), which tells us how many molecules (or atoms) are present in 1 mol of any given substance

Aₙ = 6.023 x 10²³ molecules/mol

With that in mind now we proceed to convert molecules into moles:

4.28 x 10²⁴ molecules Cl₂ ÷ 6.023 x 10²³ molecules/mol = 7.1 moles Cl₂

5 0
3 years ago
How does atomic radius change within groups and across periods in the periodic table
Aleks [24]
<span>In general,atomic size increases from top to bottom within a group and decreases from left to right across a period</span>
4 0
4 years ago
Introduction: Chemical formulas represent ratios. To make H2O, you need two atoms of H for each atom of O; you would also need t
Nina [5.8K]

Answer:

The answer to your question is given below

Explanation:

To convert from Particles to grams, one must have a clear understanding of Avogadro's hypothesis. From the Avogadro's hypothesis, we can easily convert from mole to particles and to grams.

Avogadro's hypothesis gives us a background understanding that 1 mole of any substance contains 6.02x10^23 particles. With this in mind we can easily convert particles to grams and grams to particles.

Now consider the following example:

1. How many particles are there in 4g of carbon?

Solution:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 particles. This implies that 1 mole of carbon contains 6.02x10^23 particles.

1 mole of carbon = 12g

Now we can say that 12g of carbon contains 6.02x10^23 particles.

If 12g of carbon contains 6.02x10^23 particles,

then 4g of carbon will contain = (4x6.02x10^23) /12 = 2.01x10^23 particles.

The next example will teach us how to convert from particles to grams..

2. What mass of helium contains 4.2x10^24 particles.

Solution:

According to Avogadro's hypothesis,

1 mole of He contains 6.02x10^23 particles.

1 mole of He = 4g

We can thus, say that 4g of He contains 6.02x10^23 particles.

1f 4g of He contains 6.02x10^23 particles,

Then Xg of He contains 4.2x10^24 Particles i.e

Xg of He = (4x4.2x10^24)/(6.02x10^23)

Xg of He = 27.91g

Therefore, 27.91g of He contains 4.2x10^24 Particles

With the above illustrations I believe you have understood how to convert from grams to particles and from particles to grams.

7 0
3 years ago
A layer of paint can be used to prevent iron rusting true or false​
Goshia [24]

Answer:

true

Explanation:

This layer will prevent moisture from reaching the metal and therefore prevent rust. oil paint especially

4 0
3 years ago
How many moles of solute particles are present in 1 ml of aqueous 0.020 m (nh4)2co3?
Dima020 [189]
Vs = 1.0 mL = 0.001 L
c((NH4)2CO3) = <span>0.02 M
n(</span>(NH4)2CO3) = ?

For the purpose, here we will use the next equation:

c=n/V ⇒ n=cxV

n((NH4)2CO3) = 0.02M x 0.001L 

n((NH4)2CO3) = 2x10⁻⁵ mole of (NH4)2CO3 is presented in the solution


6 0
3 years ago
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