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Andrej [43]
3 years ago
10

Power supplies used in desktop computers many years ago, commonly referred to as AT, had a power switch that switched on the 120

VAC going into the power supply. Today’s desktop computers, commonly referred to as ATX, use a power switch that sends a low-voltage logic signal to the _____.
Engineering
1 answer:
Karolina [17]3 years ago
4 0

Answer:

Power supply relay coil

Explanation:

The power supply known as ATX used in today's PCs is very complicated kind of power supply. The main objective of ATX form of the power supply is conversion of the input supply from the line into different voltages to be supplied in order to run the desktop computer's mother board.

While the AT supply that was used many years back that supplied about 120 VAC, The ATX power supply in today's world is capable of supplying power supply of about 300 W or more.

Power supply relay coil is a solitary estimation of source voltage planned by configuration to be connected to the input or coil.

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Write a program that asks the user for the name of a file. The program should display the number of words that the file contains
Flura [38]

Answer:

import java.io.*;

import java.util.Scanner;

public class CountWordsInFile {

   public static void main(String[] args) throws IOException {

       Scanner keyboard = new Scanner(System.in);

       System.out.print("Enter file name: ");

       String fileName = keyboard.next();

       File file = new File(fileName);

       try {

       

           Scanner scan = new Scanner(file);

           

           int count = 0;

           

           while(scan.hasNext()) {

               scan.next();

               count += 1;

           }

           scan.close();

           System.out.println("Number of words: "+count);        

       } catch (FileNotFoundException e) {

           System.out.println("File " + file.getName() + " not present ");

           System.exit(0);

       }

   }

}

3 0
3 years ago
Why is it important to follow the engineering design process before building a prototype
Nataly [62]

Answer:

learn from their mistakes

Explanation:

and so u could do better next time

4 0
3 years ago
Which explanation best summarizes what went wrong during Paul’s cost analysis?
Valentin [98]

Answer:

wut is it

Explanation:

4 0
2 years ago
A gasoline engine has a piston/cylinder with 0.1 kg air at 4 MPa, 1527◦C after combustion, and this is expanded in a polytropic
Roman55 [17]

Answer:

The expansion work is 71.24 kJ and heat transfer is -16.89 kJ

Explanation:

From ideal gas law,

Initial volume (V1) = nRT/P

n is the number of moles of air in the cylinder = mass/MW = 0.1/29 = 0.00345 kgmol

R is gas constant = 8314.34 J/kgmol.K

T is initial temperature = 1527 °C = 1527+273 = 1800 K

P is initial pressure = 4 MPa = 4×10^6 Pa

V1 = 0.00345×8314.34×1800/(4×10^6) = 0.013 m^3

V2 = 10×V1 = 10×0.013 = 0.13 m^3

The process is a polytropic expansion process

polytropic exponent (n) = 1.5

P2 = P1(V1/V2)^n = 4×10^6(0.013/0.13)^1.5 = 1.26×10^5 Pa

Expansion work = (P1V1 - P2V2) ÷ (n - 1) = (4×10^6 × 0.013 - 1.26×10^5 × 0.13) ÷ (1.5 - 1) = 35620 ÷ 0.5 = 71240 J = 71240/1000 = 71.24 kJ

Heat transfer = change in internal energy + expansion work

change in internal energy (∆U) = Cv(T2 - T1)

T2 = PV/nR = 1.26×10^5 × 0.13/0.00345×8314.34 = 571 K

Cv = 20.785 kJ/kgmol.K

∆U = 20.785(571 - 1800) = -25544.765 kJ/kgmol × 0.00345 kgmol = -88.13 kJ

Heat transfer = -88.13 + 71.24 = -16.89 kJ

5 0
3 years ago
Since the passing of the Utah GDL laws in 1999:
wlad13 [49]
The answer is b, I hope this helps you
7 0
3 years ago
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