Answer:
18 liters
Explanation:
Step 1: Figure out what the formula and what you are dealing with.
- 25 degrees celcius is constant, so it is irrelevant for the mathmatical part.
- P1 = 1 atm
- P2 = 20 atm
- V1 = 360 liters
- V2 = trying to find
Note: remember the original equation is V1/P1 = V2/P2
- Step 2: Rearrange the equation to fit this problem, you should get...
V2 = V1 x P1 / P2
- Step 3: Fill our own numbers in. You should get...
360 L x 1 atm / 20 atm = 18 Liters (do the math)
- Answer = 18 Liters
- Remember to just follow the formula and fill it in with your own numbers.
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Answer:
creation of radioactive wastes such as uranium mill tailings, spent (used) reactor fuel, and other radioactive wastes.
Explanation:
Nuclear energy produces radioactive waste
A major environmental concern related to nuclear power is the creation of radioactive wastes such as uranium mill tailings, spent (used) reactor fuel, and other radioactive wastes. These materials can remain radioactive and dangerous to human health for thousands of years.
Answer:
Mass= 2.77g
Explanation:
Applying
P=2.09atm, V= 1.13L, R= 0.082, T= 291K, Mm of N2= 28
PV=nRT
NB
Moles(n) = m/M
PV=m/M×RT
m= PVM/RT
Substitute and Simplify
m= (2.09×1.13×28)/(0.082×291)
m= 2.77g
Mg + Cl₂ = MgCl₂M(Mg) = 24г/моль m 1 моль Mg = 24 г.По условию задачи дано 12г. Mg Количество вещества n(Mg) =12÷24=0,5 мольРассуждаем: по уравнению реакции с 1 моль магния реагирует 1 моль хлора, следовательно с 0,5 моль будет реагировать 0,5 моль хлора.1 моль хлора при н.у. занимает объем 22,4л. , тогда 0,5 моль хлора займет:0,5х22,4л.= 11,2л. Ответ: Для взаимодействии 12 г. магния потребуется 11,2 л. хлора.
Answer:
✨ science ✨ and ✨ big brain stuff ✨
Explanation:
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