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nikitadnepr [17]
3 years ago
9

The sun emits radiation, which reaches the Earth

Chemistry
1 answer:
ololo11 [35]3 years ago
6 0
Options if it’s true or false true
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A sample of CH4 is confined in a water manometer. The temperature of the system is 30.0 °C and the atmospheric pressure is 98.70
kakasveta [241]

Explanation:

The given data is as follows.

  P_{atm} = 98.70 kPa = 98700 Pa,  

      T = 30^{o}C = (30 + 273) K = 303 K

      height (h) = 30 mm = 0.03 m (as 1 m = 100 mm)

Density = 13.534 g/mL = 13.534 g/mL \times \frac{10^{6}cm^{3}}{1 m^{3}} \times \frac{1 kg}{1000 g}

                = 13534 kg/m^{3}

The relation between pressure and atmospheric pressure is as follows.

             P = P_{atm} + \rho gh

Putting the given values into the above formula as follows.

            P = P_{atm} + \rho gh

               = 98700 Pa + 13534 \times 9.81 \times 0.03 m

               = 102683.05 Pa

               = 102.68 kPa

thus, we can conclude that the pressure of the given methane gas is 102.68 kPa.

8 0
4 years ago
You titrate 25.0 mL of HCl solution of an unknown concentration with a 0.190 M NaOH solution. Complete neutralization of the HCl
galina1969 [7]

A titration is defined as 'the process of determining the quantity of a substance A by adding measured increments of substance B, the titrant, with which it reacts until exact chemical equivalence is achieved (the equivalence point)'.

The Molarity of the HCl Solution requires the addition of 24.6 mL of titrant is 0.0836 M (to 3 significant figures)

<h3>What is Titrant?</h3>

A reagent solution of precisely known concentration that is added in titration

Given reaction HCl + NaOH ===> NaCl + H_2O  neutralization reaction

Note that the mole ratio is 1:1 meaning that 1 mole HCl reacts with 1 mole NaOH to produce 1 mole NaCl and 1 mole H_2O

Find moles of NaOH used:

18.45 ml x 1 L/1000 ml x 0.085 mol/L = 0.002091 moles NaOH used

This meant that there must be 0.002091 moles of HCl present in the 25.0 mls.

We want to find the molarity (M) which is moles HCl/liter of solution.  We know the moles, and we also know the liters of solution (25.0 mls x 1 L / 1000 mls = 0.025 liters)

M = 0.002091 moles HCl / 0.025 liters = 0.08364 M = 0.0836 M (to 3 significant figures)

Learn more about Titration Here;
brainly.com/question/27107265

#SPJ1

4 0
2 years ago
By definition 12 grams of carbon-12 must contain how many atoms?
krek1111 [17]
It is defined as the amount of a substance that contains as many particles as there are atoms in 12 grams of pure carbon-12. So, 1 molecule contains 6.022×10^23 elementary entities of the substance.

Hope that helps
5 0
4 years ago
Chemical barriers include? mucous food hydrochloric acid sweat
mr Goodwill [35]

Enzymes that eventually break down the surface of bacteria are found in saliva, mucus, and tears, which act as chemical barriers against infection.

Enzymes found in saliva, mucous, as well as tears that degrade bacterial surfaces serve as chemical barriers preventing infection. The stomach's acid as well as the acid in sweat both destroy cellular pathogens, and even the semen contains antibacterial proteins.

There is no chemical and physical barrier offered by macrophages. Instead of acting as a barrier, macrophages target pathogens once they have already entered the body. Physical barriers include mucus as well as stratified squamous epithelium, whereas chemical barriers include saliva and urine.

Therefore, Enzymes that eventually break down the surface of bacteria are found in saliva, mucus, and tears, which act as chemical barriers against infection.

To know more about chemical barriers

brainly.com/question/20725429

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4 0
1 year ago
The combustion of 0.25 mol of an unknown organic compound results in the release of 320 kJ of energy. Which of the compounds in
vichka [17]

Answer: C. ethanol

The enthalpy of combustion is the amount of heat produced when one mole of ethanol undergoes complete combustion at 25 ° C and 1 atmosphere pressure, yielding products also at 25 ° C and 1 atm.

<u>The enthalpy of combustion of the unknown compound is</u>

ΔH = - 320 kJ / 0.25 mol = - 1280 kJ / mol

<u>To choose a probable compound according to this combustion enthalpy, we must evaluate the deviation in relation to the values reported in the literature for the three probable compounds</u> (methane, ethylene and ethanol). The deviation (e%) will be calculated according to the following equation,

e% =  ( | ΔHx - ΔH | / ΔHx ) x 100%

where ΔHx is the enthalpy of combustion of the probable compound.

The following table shows the combustion enthalpies of the probable compounds and their deviation in relation to the enthalpy of ΔH = - 1280 kJ / mol

Compound Enthalpy of combustion (kJ/mol)   Deviation

Methane                        - 890.7                                 43.8%

Ehylene                         -1411.2                                   9.3%

Ethanol                        -1368.6                                    6.5%

According to the previous table, we can say that the most probable compound is ethanol, since it has the smallest deviation in relation to the experimental enthalpy value of combustion.

5 0
4 years ago
Read 2 more answers
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