A 5.50-kg bowling ball moving at 9.00 m/s collides with a 0.850-kg bowling pin, which is scattered at an angle of \text{85}\text
{.}0º to the initial direction of the bowling ball and with a speed of 15.0 m/s. (a) Calculate the final velocity (magnitude and direction) of the bowling ball. (b) Is the collision elastic? (c) Linear kinetic energy is greater after the collision. Discuss how spin on the ball might be converted to linear kinetic energy in the collision.
1 answer:
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Explanation:
Expression to calculate thermal resistance for iron () is as follows.
where, = length of the iron bar
= thermal conductivity of iron
= Area of cross-section for the iron bar
Thermal resistance for copper () = \frac{L_{c}}{k_{c} \times A_{c}}[/tex]
where, = length of copper bar
= thermal conductivity of copper
= Area of cross-section for the copper bar
Now, expression for the transfer of heat per unit cell is as follows.
Q =
Putting the given values into the above formula as follows.
Q =
=
= 2.92 Joule
It is known that heat transfer per unit time is equal to the power conducted through the rod. Hence,
P =
Here, T is 1 second so, power conducted is equal to heat transferred.
So, P = 2.92 watt
Thus, we can conclude that 2.92 watt power will be conducted through the rod when it reaches steady state.
Answer:
radius comes out to be 3 m
height of the cylinder comes out to be 3m
Explanation:
given
volume of cylinder = 27π m³
π r² h = 27π
r² h = 27.............(1)
surface area of cylinder open at the top
S = 2πrh + π r²
for least amount of material requirement.
hence radius comes out to be 3 m
for height put the value in the equation 1
so, height of the cylinder comes out to be 3m