Answer:
Which of the following pairs lists a substance that can neutralize Ca(OH)2 and the salt that would be produced from the reaction?
HCl and CaCl2
HClO and CaHClO
H2O and Ca(OH)3
H3PO4 and Ca(PO3)2
Explanation:
The given substance is Ca(OH)2 which is a base.
To neutralise a base an acid is required.
Among the given options,
HCl and H3PO4 are the acids.
The salts foremd when calcium hydroxide reacts with the respective acids are CaCl2 and Ca3(PO4)2.
But among the given options, only the forst option that is
HCl and CaCl2 shows the correct formulas.
Hence, the answer is first option.
We are given with a theoretical amount of 9 grams of product but the student only got 7.8 grams. To calculate the percent yield, we divide the experimental amount by the theoretical amount. In this case, we divide 7.8 grams by 9 grams and multiply by 100 percent. The answer is equal to 86.67 percent.
A control group is the comparison group that helps to "make sure your experiment works." A control group is separated from the rest of the experiment and nothing happens to it kinda like a controlled variable. Controlled variables are the variables in a experiment that remains the same for example a temperature, time, type of products, etc..
Hope this helps!
Answer:p-hydroxybenzaldehyde is stronger acid to phenol
para-cyanophenol is stronger acid to meta-cyanophenol
o-fluorophenol is stronger acid to p-fluorophenol.
Explanation:
The PKa tool relative to Ph are used to contrast the pairs.
The pKa of phenol is 10. The pKa of p-hydroxybenzaldehyde is 9.24
The pKa for meta-cyanophenol is 8.61 and the pKa for para-cyanophenol is 7.95.
The pKa value of o-fluorophenol is 8.7, while that of the p-fluorophenol is 9.9. It's obvious that the inductive effect is more dominant at ortho-position, which results in a more acidic nature
The pKa is the pH value at which a chemical species will accept or donate a proton. The lower the pKa, the stronger the acid and the greater the ability to donate a proton in aqueous solution.