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3 years ago

How many molecules are present in a drop of ethanol, c2h5oh, of mass 2.310^-2.3g? (NA=6.010^23mol^-1)

Chemistry

1 answer:

sdas [7]3 years ago

5 0

Answer:

3.0 × 10²⁰ molecules

Explanation:

Given data:

Mass of ethanol = 2.3 × 10⁻²°³ g

Number of molecules = ?

Solution:

Number of moles of ethanol:

Number of moles = mass/ molar mass

Number of moles = 2.3 × 10⁻²°³ g / 46.07 g/mol

Number of moles = 0.05 × 10⁻²°³ mol

Number of molecules:

One mole = 6.022 × 10²³ molecules

0.05 × 10⁻²°³ mol × 6.022 × 10²³ molecules / 1 mol

0.30 × 10²⁰°⁷ molecules

3.0 × 10¹⁹°⁷ molecules which is almost equal to 3.0 × 10²⁰ molecules.

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3 years ago

How many molecules are present in a drop of ethanol, c2h5oh, of mass 2.3*10^-2.3g? (NA=6.0*10^23mol^-1)

How many molecules are present in a drop of ethanol, c2h5oh, of mass 2.310^-2.3g? (NA=6.010^23mol^-1)