7 - Neutral because water and salt are neutral substances
Answer:
Both metals and non metals.
Explanation:
The correct formula of baking soda is NaHCO₃,
An element is considered to be metal if it is able to give electron easily due to very low ionization energy.
A non metal is ready to accept electron easily due to high electron affinity.
In sodium bicarbonate :
Na: Sodium : metal
H : Hydrogen: non metal (although placed with first group, alkali metals, in the periodic table as it readily loses electron like metals)
C: Carbon: Non metal
O : Oxygen : Non metal.
So the compound contains both metals and non metals.
Answer:
moles of ammonia produced = 0.28 moles
Explanation:
The reaction is
As per equation, one mole of nitrogen will react with three moles of hydrogen to give two moles of ammonia
So 0.140 moles of nitrogen will react with = 3 X 0.140 moles of Hydrogen
= 0.42 moles of hydrogen molecule.
this will give 2 X 0.140 moles of ammonia = 0.28 moles of ammonia
the moles of ammonia produced = 0.28 moles
Here the nitrogen is limiting reagent.
The answer is 60.3% magnesium, 39.7% oxygen.
Solution:
The chemical equation for the reaction is 2 Mg + O2 → 2 MgO.
Since magnesium reacts completely with oxygen, it is the limiting reactant in the reaction. Hence, we can use the number of moles of magnesium to get the mass of MgO produced:
moles of magnesium = 14.7g / 24.305g mol-1
= 0.6048 mol
mass of MgO = 0.6048mol Mg(2 mol MgO/2mol Mg)(40.3044g MgO/1 mol MgO)
= 24.376g MgO
We can now solve for the percentage of magnesium:
% Mg = (14.7g Mg / 24.376g MgO)*100% = 60.3%
We also use the number of moles of magnesium to get the mass of oxygen consumed in the reaction:
mass of O2 = 0.6048 mol Mg (1mol O2 / 2mol Mg) (31.998g / 1mol O2)
= 9.676g
The percentage of oxygen is therefore
% O2 = (9.676g O2 / 24.376g MgO)*100%
= 39.7%
Notice that we can just subtract the magnesium's percentage from 100% to get
% O2 = 100% - 60.3% = 39.7%
Fluorine has 9 protons and 9 electrons
Iodine has 53 protons and 53 electrons
