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3 years ago

Which class of compunds has the general formula r-o-r

Chemistry

1 answer:

Hatshy [7]3 years ago

4 0

Answer:

R-O-R is the general formula for Symmetrical Ethers,in which both alkyl groups attached on oxygen are same .

Explanation:

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tensa zangetsu [6.8K]

Explanation:

a) HNO2(aq) = HNO3(aq) + H2O(l) +NO(g)

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c) CH4 (g) + 2O2(g) = Co2 (g) + 2H2O(g)

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2 years ago

HELP PLZ

Vinvika [58]

Answer:

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2 years ago

Convert 5.4g of NaCl to moles

sammy [17]

Answer:

.0924 moles of NaCl

Explanation:

So you know you have 5.4 g of NaCl and you need to know how many moles there are in this amount of NaCl

You'll need to find the atomic mass of the compound NaCl to help you solve for moles

Sodium (Na) on the periodic table has a mass of 22.99

Chlorine (Cl) on the periodic table has a mass of 35.45

Add these two together----> 22.99 + 35.45 = 58.44

Now you can calculate for moles

Written-out method:

5.4 grams of NaCl | 1 mole of NaCl

| 58.44 grams NaCl = .0924 moles of NaCl

Plug into calculator method:

(5.4 g of NaCl/ 58.44g NaCl= .0925 moles)

7 0

2 years ago

Which of the following is not a possible termination step in the free radical chlorination of methane? Group of answer choices ∙

vagabundo [1.1K]

Answer: first option is not a termination

∙CH3 + Cl2 → CH3Cl + Cl∙

Explanation:

Since a radical is formed as part of the product it means it's a propagation step and not a termination step, at termination no free radical exist as product

7 0

3 years ago

Antarctica, almost completely covered in ice, has an area

Marysya12 [62]

Answer: The mass of ice is $2.39\times 10^{22}g$

Explanation:

We are given:

Area of Antarctica = $5,500,000mi^2=5,500,000\times 2.59\times 10^{10}=142.45\times 10^{15}cm^2$ (Conversion factor: $1mi^2=2.59\times 10^{10}cm^2$ )

Height of Antarctica with ice = 7500 ft.

Height of Antarctica without ice = 1500 ft.

Height of ice = 7500 - 1500 = 6000 ft = $182.88\times 10^3cm$ (Conversion factor: 1 ft = 30.48 cm)

To calculate mass of ice, we use the equation:

$\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}$

We are given:

Density of ice = $0.917g/cm^3$

Volume of ice = Area × Height of ice = $142.45\times 10^{15}cm^2\times 182.88\times 10^3cm=26051.26\times 10^{18}cm^3$

Putting values in above equation, we get:

$0.917g/cm^3=\frac{\text{Mass of ice}}{26051.26\times 10^{18}cm^3}\\\\\text{Mass of ice}=(0.917g/cm^3\times 26051.26\times 10^{18}cm^3=2.39\times 10^{22}g$

Hence, the mass of ice is $2.39\times 10^{22}g$

5 0

2 years ago

Which class of compunds has the general formula r-o-r​

Which class of compunds has the general formula r-o-r