To summarize, Jane's star has a red light and is traveling towards the Earth while John's star has a blue light and is traveling away from the Earth. This is a prime example of the Doppler Effect in motion. The stars look different because they are traveling in different directions.

4 0

3 years ago

Does anyone know how to do this question??? Force = 7kN Pressure = 1mPa Area = ?

Andreas93 [3]

Answer:

7000 m^2

Explanation:

Pressure=Force/Area

1=7000/Area

1(Area)=7000

Area=7000 m^2

5 0

2 years ago

You are on a new planet, and are trying to use a simple pendulum to find the gravity experienced on this new planet. You find th

levacccp [35]

To solve this problem it is necessary to apply the concepts related to the Period based on the length of its rope and gravity, mathematically it can be expressed as

$T= 2\pi \sqrt{\frac{L}{g}}$

g = Gravity

L = Length

T = Period

Re-arrange to find the gravity we have

$g = \frac{4\pi^2 L}{T^2}$

Our values are given as

$L = 0.35m\\T = 2s\\$

Replacing we have

$g = \frac{4\pi^2 L}{T^2}$

$g = \frac{4\pi^2 0.35}{2^2}$

$g = 3.45 m/s^2$

Therefore the correct answer is C.

4 0

3 years ago

What is the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosp

sineoko [7]

The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

To find the answer, we have to know about the pressure.

<h3>How to find the weight of a column of air?</h3>

As we know that the expression of pressure as,

$P=\frac{F}{A}$

where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.

It is given that, the air column is extending from earth's surface to the top of the atmosphere, thus, the pressure will be atmospheric pressure,

$P=1atm=1.013*10^5Pascals$

From this, the value of weight will be,

$F=mg=P*A=1.013*10^5*4.5=4.56*10^5N$

Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

Learn more about the pressure here:

brainly.com/question/12830237

#SPJ4

4 0

1 year ago