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fomenos
2 years ago
5

A heavy boy and a lightweight girl are balanced on a massless seesaw. The boy moves backward, increasing his distance from the p

ivot point. What happens to the seesaw?.
Physics
1 answer:
kumpel [21]2 years ago
3 0
A see saw is a class one lever. It moves from one center joint and moves only up or down. As the boy backs up from the middle of the seesaw his mass will weigh him down and lift the girl.
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The weight of an astronaut on the moon is the same as on Earth.<br> True<br> False
Vaselesa [24]

Answer:

False

Explanation:

This is due to the gravitational pull, since the moon does not have the same force or gravity like Earth, your weight would change.

☆anvipatel77☆

•Expert•

Brainly Community Contributor

5 0
3 years ago
Read 2 more answers
A photon of wavelength 3.7 nm Compton scatters from an electron at an angle of 90°. What is the modified wavelength? (Enter your
viva [34]

Answer:

3.70242 nm

Explanation:

Using Compton effect formula

Δλ = ( h / mec) ( 1 - cosθ)

where h is planck constant = 6.62607 × 10 ⁻³⁴ m²kg/s

me, mass of an electron = 9.11 × 10⁻³¹ kg

c is the speed of light = 3 × 10⁸ m/s

Δλ = 6.62607 × 10 ⁻³⁴ m²kg/s / (9.11 × 10⁻³¹ kg × 3 × 10⁸ m/s ) ( 1 - cos 90°) =   0.242 × 10 ⁻¹¹ m = 2.42 × 10⁻¹² m  = 0.00242 nm

modified wavelength = 3.7 nm + 0.00242 nm = 3.70242 nm

7 0
4 years ago
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A rope has a mass of 10.43 pounds per meter. Express this in milligrams per centimeter.
gregori [183]

Answer:

47347.1936 milligrams per centimeter

Explanation:

1 pound is equal 453592 milligrams.

one meter is 100cm

10.43*453952/100= 47347.1936milligrams per cm

3 0
4 years ago
A car moving at 16.0 m/s, passes an observer while its horn is pressed. the velocity of sound is 343 m/s and the frequency of th
Arada [10]
We are asked to solve for the frequency heard when a car is coming towards the observer. The car is moving at 16 m/s and the velocity of the sound is 343 m/s where the car horns at 583 Hz. We will use Doppler's Effect formula in calculating the unknown frequency such that the solution is shown below:
Fl = (V + Vl) * Fs / (V - Vs)
FL = (343 + 0)*583 / (343 - 16)
FL = 611. 53 Hertz

The answer for the frequency of the observer is 611.53 hertz.
5 0
3 years ago
NEED Answer asap plz!!
stira [4]

Answer:

I think a is the right not clear but

7 0
3 years ago
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