Question

Write the expression as a polynomial: (b–c)(b2–bc–c2)(3y–4)

Answer 1

Answer:

 $3b^3y-6b^2cy+3c^3y-4b^3+8b^2c-4c^3$

Step-by-step explanation:

The given expression is

$(b-c)(b^2-bc-c^2)(3y-4)$.

We expand the first two parenthesis to get,

 $(b^3-2b^2c+c^3)(3y-4)$

We now expand again to get,

 $3y(b^3-2b^2c+c^3)-4(b^3-2b^2c+c^3)$

This will give us

  $3b^3y-6b^2cy+3c^3y-4b^3+8b^2c-4c^3$