The volume of acetone, in milliliters, has a mass of 44.2 g is 55.96mL.
<h3>HOW TO CALCULATE VOLUME?</h3>
The volume of a substance can be calculated by dividing the mass by its density. That is;
Volume (mL) = mass (g) ÷ density (g/mL)
According to this question, acetone is a solvent with density of 0.7899g/mL and mass of 44.2g. The volume is calculated as follows:
Volume = 44.2g ÷ 0.7899g/mL
Volume = 55.96mL
Therefore, the volume of acetone, in milliliters, has a mass of 44.2g is 55.96mL.
Learn more about volume at: brainly.com/question/1578538
Answer:
346.g of solution
Explanation:
In this case, if we have 5.2 % by mass it means that in <u>100 g of the solution we will have 5.2 g of glucose</u>. Therefore we can do the calculation:
<u>5.2 g of glucose = 100 g of solution</u>
So, if we need 8 g of glucose we had to have 346.15 g of solution
This logic can work for all types of solutions. By mass (as in this case), by volume or mass/volume.
I hope it helps!
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Answer:
20.446cm3
Explanation:
The following were obtained from the question given:
V1 (initial volume) = 24.568 cm3
T1 (initial temperature) = 25°C = 25 + 273 = 298K
T2 (final temperature) = - 25°C = - 25 + 273 = 248K
V2 (final volume) = ?
Since the pressure is constant, the gas is obeying Charles' law. With the Charles' law equation V1/T1 = V2/T2, we can easily calculate the final volume as follow:
V1/T1 = V2/T2
24.568/298 = V2/248
Cross multiply to express in linear form as shown below:
298 x V2 = 24.568 x 248
Divide both side by 298
V2 = (24.568 x 248) /298
V2 = 20.446cm3
From the calculations made above, the volume of the gas at -25°C is 20.446cm3
