Answer:
a) u = 6 m/s
b) a = 4 m/s²
c) d(3) = 16 m
Explanation:
equation for the first second
distance will be the average velocity times the time of travel
8 = ½(u + (u + at))t t is one second, so reduces to
8 = u + ½a
velocity at the end of the first second is
v = u + at = u + a
position equation for the second period is
12 = ½((u + a) + (u + a + at))t t is one second so reduces to
12 = u + 3a/2
subtracting the first position equation from the second
12 - 8 = u + 3a/2 - (u + ½a)
a = 4 m/s²
8 = u + ½4
u = 6 m/s
in the third second
d = 6(3) + ½(4)(3²) - 8 - 12
d = 16 m
Answer:
a= -1.01m/s^2
Explanation:
A) We define all the variables that are given,
In this way
Acceleration = a
We obtain the Normal assuming 5% of the potato reading scale, so
We add forces to reach equilibrium, and you get
** The notation of the symbols is done according to the notation of the graph
So,
B) When making pressure it is understood that the shape takes the perpendicular direction of the direction of the force that is performed. If the pressure remains constant, the scale will also increase in its measurement.
To solve this exercise,
the following speed equation must be applied:
V = d / t (mi/hr)
V: speed (mi/hr)
d: distance (mi)
t: time (s)
We know the distance (d= 5 miles) and the time (t= 0.2 hours), so
we proceed to replace these values in the formula to calculate the lion’s speed:
V = d / t
V = 5 mi/0.2 hr
V = 25 mi/hr
The lion’s speed is 25
mi/hr, so the last option is the right answer
Answer:
Explanation:
The formula P=VI, just rearrange to find I
So
I=P/V
=75/120
=0.625amps
625mA