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Brrunno [24]
3 years ago
8

What type of current is produced by a battery?

Physics
1 answer:
padilas [110]3 years ago
8 0
The positive plate is made of lead grid with a lead oxide paste coating and the negative plate is porous lead. Dilute sulphuric acid is the electrolyte. The lead acid battery produced a direct current or DC during a chemical reaction that turns lead dioxide to lead sulphate and sulphuric acid to water.
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A 20 g bullet is shot from a 10 kg gun with a velocity of 400 m/s. What
Nady [450]

Answer: -.80m/s

Explanation:

3 0
3 years ago
1- A 30 gram bullet travels at 300 m/s. How much kinetic energy does it have?
labwork [276]

Answer:

1.35 kJ  

Explanation:

KE = ½mv² = ½ × 0.030  kg × (300 m·s⁻¹)² = 1350 J = 1.35 kJ

7 0
3 years ago
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A length of copper wire carries a current of 14 A, uniformly distributed through its cross section. The wire diameter is 2.5 mm,
gavmur [86]

Answer:

a. ρ_\beta=1.996J/m^3

b. U_E=9.445x10^{-15} J/m^3

Explanation:

a. To find the density of magnetic field given use the gauss law and the equation:

i=14A, d=2.5mm, R=3.3Ω, l=1 km, E_o=8.85x10^{-12}F/m, u_o=4*x10^{-7}H/m

ρ_\beta=\frac{\beta^2}{2*u_o}

ρ_\beta=\frac{1}{2*u_o}*(\frac{u_o*i^2}{2\pi *r})^2

ρ_\beta=\frac{u_o*i^2}{8\pi*r}=\frac{4\pi *10^{-7}H/m*(14A)^2}{8\pi*(1.25x10^{-3}m)^2}

ρ_\beta=1.996J/m^3

b. The electric field can be find using the equation:

U_E=\frac{1}{2}*E_o*E^2

E=(\frac{i*R}{l})^2

U_E=\frac{1}{2}*8.85x10^{-12}*(\frac{14A*3.3}{1000m})^2

U_E=9.445x10^{-15} J/m^3

4 0
3 years ago
Why are peer reviews important?
Pavlova-9 [17]

Answer:

Peer reviews are important because individuals with similar background knowledge are used to review work to detect inaccuracies or deficiencies in the work.

Explanation:

Those individuals with similar educational and work background knowledge can more accurately review work since they have the required knowledge base for the subject.

7 0
3 years ago
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A butterfly flies from the top of a tree in the center of a garden to rest on top of a red flower at the garden's edge. The tree
Zielflug [23.3K]

The butterfly takes a vertical perpendicular path equivalent to 9m and travels a horizontal distance of 17m. The net path between the two is equivalent to that of the hypotenuse, so we will apply the Pythagorean theorem.

x=\sqrt{(9)^2+(0.17)^2}

x = 9.0061 \approx 9.0 m

Therefore the magnitude of the butterfly's displacement is 9m

3 0
3 years ago
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