Ask question

Ask question

All categories

3 years ago

8

A water wave travels 36 meters in 15 seconds. What is the speed of the wave?

2 answers:

Arisa [49]3 years ago

4 0

Since the question above is looking for the SPEEd of the WAVE, the formula that should be used is SPEED = DISTANCE / TIME. You just need to substitute the distance (36 meters) and the time (15 seconds) to the formula. You should be able to get SPEED = 2.4 m/s.

scoundrel [369]3 years ago

4 0

A water wave travels 36 meters in 15 seconds. What is the speed of the wave?

2.4 m/s

You might be interested in

I will be so thankful if u answer correctly!!

polet [3.4K]

(C) 200 N

Explanation:

The acceleration due to gravity on earth $g_{E}$ is given by

$g_{E} = G\dfrac{M_{E}}{R_{E}^{2}}$

where $G$ = universal gravitational constant

$\:\:\:\:\:\:\:\:\:\:\:\:M_{R}$ = mass of the earth

$\:\:\:\:\:\:\:\:\:\:\:\:R_{E}$ = radius of the earth

Planet Krypton has twice the mass of earth and 3 times the radius so its acceleration due to gravity $g_{K}$ is

$g_{K} = G\dfrac{M_{K}}{R_{K}^{2}}$

$\:\:\:\:\:\: = G\dfrac{(2M_{E})}{(3R_{E})^{2}}$

$\:\:\:\:\;\:= (\dfrac{2}{9})G\dfrac{M_{E}}{R_{E}^{2}}$

or

$g_{K} = (\dfrac{2}{9})\:g_{E}$

If we multiply both sides by Superman's mass, we get his weights on both planets:

$mg_{K} = (\dfrac{2}{9})\:(mg_{E})$

$W_{K} = (\dfrac{2}{9})\:W_{E} = (\dfrac{2}{9})(900\:N)= 200\:N$

3 0

3 years ago

Someone help me pls I will give brainlist

sergeinik [125]

Answer:

the answer is point no. a °C , c. K and d. °F

6 0

4 years ago

Read 2 more answers

Which state(s) of matter is/are made up of atoms and molecules that have a comparatively high amount of kinetic energy, which al

Rom4ik [11]

Answer:

A. gas only

Explanation:

In a gas, the molecules are in continuous, random, straight-line motion.

The molecules are independent of one another i.e The forces of attraction (cohesive forces) and repulsion between the molecules are small and negligible,As such they possess greater kinetic energy which allows them to break the force of attraction between them

In liquid, the molecules have a less random pattern of motion and they can only slide past one another.

In solid, the motion are restricted to a small place as the molecules are not free to move about but merely vibrate about their lattice points.

7 0

3 years ago

Three persons wants to push a wheel cart in the direction marked x in Fig. The two person push with horizontal forces F1 and F2

Svetllana [295]

Answer:

<u>I had to search the Figure on Google to solve this question.</u>

a) The magnitude of the force F₃ is:

$F_{3} = 87.47 N$

And the direction of F₃:

$\alpha = 79.04 ^{\circ}$ (with respect to the y-direction, in the third quadrant)

b) P = 4.22 N

Explanation:

<u>I had to search the Figure on Google to solve this question.</u>

a) We can find the force of the third person as follows:

$\Sigma F_{x} = F_{1x} + F_{2x} + F_{3x} = 0$

$\Sigma F_{y} = F_{1y} - F_{2y} + F_{3y} = 0$

So, in x-direction we have:

$\Sigma F_{x} = 45 N*cos(70) + 75 N*cos(20) + F_{3x} = 0$

$F_{3x} = -85.87 N$

In y-direction we have:

$\Sigma F_{y} = 45 N*sin(70) - 75 N*sin(20) + F_{3y} = 0$

$F_{3y} = -16.63 N$

The magnitude of the force F₃ is:

$F_{3} = \sqrt{F_{3x}^{2} + F_{3y}^{2}} = \sqrt{(-85.87 N)^{2} + (-16.63 N)^{2}} = 87.47 N$

To find the direction of F₃ we need to calculate its angle with respect to the y-direction (in the third quadrant):

$tan(\alpha) = \frac{|F_{3x}|}{|F_{3y}|} = \frac{85.87 N}{16.63 N}$

$\alpha = 79.04 ^{\circ}$

<em>b) If the third person exerts the force found in part (a) the car will stop, so the only way for the cart to accelerate at 200 m/s² is that the third person does not exert the force found in a. </em>

<u>To find the weight of the cart when it accelerates at 200 m/s², we need to consider: F₃ = 0</u>.

First, we need to find the cart's mass. Since the car is moving in the x-direction we have:

$\Sigma F_{x} = F_{1x} + F_{2x} = ma$

$45 N*cos(70) + 75 N*cos(20) = m*200 m/s^{2}$

$m = \frac{45 N*cos(70) + 75 N*cos(20)}{200 m/s^{2}} = 0.43 kg$

Now, the weight of the cart is:

$P = mg = 0.43 kg*9.81 m/s^{2} = 4.22 N$

I hope it helps you!

3 0

3 years ago

The voltage across a membrane forming a cell wall is 74.0 mV and the membrane is 9.20 nm thick. What is the electric field stren

Sindrei [870]

Answer:

7.60× 10^6 V/m

Explanation:

electric field strength can be determined as ratio of potential drop and distance, I.e

E=V/d

Where E= electric field

V= potential drop= 74.0 mV= 0.07 V

d= distance= 9.20 nm = 9.2×10^-9 m

Substitute the values

E= 0.07/ 9.2×10^-9

= 7.60× 10^6 V/m

5 0

3 years ago