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Vsevolod [243]
3 years ago
9

What TWO things happen to solar radiation that reaches earth?

Physics
2 answers:
-Dominant- [34]3 years ago
4 0
The energy of the reflected radiation<span> goes back into outer space. The other 70% of </span>solar<span> radiation that gets to </span>Earth<span> is absorbed. Most of the energy is absorbed by oceans, landforms, and living </span>things<span>. </span>
padilas [110]3 years ago
4 0
The radiation is absorbed and most of the energy is absorbed and stored in oceans, landscapes and in living things
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A 6.00-mH solenoid is connected in series with a 5.0-μF capacitor and an AC source. The solenoid has internal resistance 3.0 Ω w
son4ous [18]

Answer:

5773.50269 Hz

23 A

Explanation:

L = Inductance = 6 mH

C = Capacitance = 5 μF

R = Resistance = 3 Ω

\epsilon = Maximum emf = 69 V

Resonant angular frequency is given by

\omega=\dfrac{1}{\sqrt{LC}}\\\Rightarrow \omega=\dfrac{1}{\sqrt{6\times 10^{-3}\times 5\times 10^{-6}}}\\\Rightarrow \omega=5773.50269\ Hz

The resonant angular frequency is 5773.50269 Hz

Current is given by

I=\dfrac{\epsilon}{R}\\\Rightarrow I=\dfrac{69}{3}\\\Rightarrow I=23\ A

The current amplitude at the resonant angular frequency is 23 A

7 0
3 years ago
Vascular plants can be divided into three categories. These categories are
Evgesh-ka [11]
I believe the answer here is <span>C).seedless, seed (nonflowering), and seed (flowering).</span><span>
</span>
6 0
3 years ago
Identify the two pieces of information you need to know the velocity of an object
Georgia [21]
Manuel with and height?
8 0
3 years ago
A muon has a rest mass energy of 105.7 MeV, and it decays into an electron and a massless particle. If all the lost mass is conv
sergeinik [125]

Answer:

The electron’s velocity is 0.9999 c m/s.

Explanation:

Given that,

Rest mass energy of muon = 105.7 MeV

We know the rest mass of electron = 0.511 Mev

We need to calculate the value of γ

Using formula of energy

K_{rel}=(\gamma-1)mc^2

\dfrac{K_{rel}}{mc^2}=\gamma-1

Put the value into the formula

\gamma=\dfrac{105.7}{0.511}+1

\gamma=208

We need to calculate the electron’s velocity

Using formula of velocity

\gamma=\dfrac{1}{\sqrt{1-(\dfrac{v}{c})^2}}

\gamma^2=\dfrac{1}{1-\dfrac{v^2}{c^2}}

\gamma^2-\gamma^2\times\dfrac{v^2}{c^2}=1

v^2=\dfrac{1-\gamma^2}{-\gamma^2}\times c^2

Put the value into the formula

v^2=\dfrac{1-(208)^2}{-208^2}\times c^2

v=c\sqrt{\dfrac{1-(208)^2}{-208^2}}

v=0.9999 c\ m/s

Hence, The electron’s velocity is 0.9999 c m/s.

6 0
3 years ago
Need help finding the average speed.
Snowcat [4.5K]

Explanation:

To find the average of these numbers, we just have to add the three numbers together and divide by 3.

  • 2.07 + 0. 74 + 1.33 = 4.14. 4.14 / 3 = 1.38
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5 0
3 years ago
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