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stealth61 [152]
3 years ago
8

The vapor pressure of methanol at 25 is 0.1663 . Calculate the vapor pressure in kPa . Be sure your answer has the right number

of significant digits.
Chemistry
1 answer:
skad [1K]3 years ago
7 0

Answer:

16.8 kPa is the vapor pressure of CH₃OH in kPa

Explanation:

Vapor pressure of CH₃OH is 0.1663 atm (you missed the unit in the statement)

To make the convertion, we know that:

1 atm = 101.3 kPa

0.1663 atm . 101.3 kPa / 1atm = 16.8 kPa

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If the solubility of a gas is 10.5 g/L at 525 kPa pressure, what is the solubility of the gas when the pressure is 225 kPa? Show
Talja [164]

Answer:

4.5 g/L.

Explanation:

  • To solve this problem, we must mention Henry's law.
  • Henry's law states that at a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.
  • It can be expressed as: P = KS,

P is the partial pressure of the gas above the solution.

K is the Henry's law constant,

S is the solubility of the gas.

  • At two different pressures, we have two different solubilities of the gas.

<em>∴ P₁S₂ = P₂S₁.</em>

P₁ = 525.0 kPa & S₁ = 10.5 g/L.

P₂ = 225.0 kPa & S₂ = ??? g/L.

∴ S₂ = P₂S₁/P₁ = (225.0 kPa)(10.5 g/L) / (525.0 kPa) = 4.5 g/L.

8 0
3 years ago
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Answer:

I could I guess?

But like only 1 lol

Explanation:

6 0
3 years ago
the burning of wood is a chemical reaction between cellulose molecules in the wood and oxygen the products are carbon dioxide an
Sati [7]

Put the <em>wood and excess oxygen in a closed contai</em>ner that contains some device that can create a spark (to start the reaction).

Determine the <em>mass of container + contents</em>.

<em>Start the reaction</em> and, after everything has cooled down, again determine the <em>mass of container + contents</em>.

If the two masses are the same, you have demonstrated that the reaction obeys the Law of Conservation of Mass.

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Using the following equation for the combustion of octane calculate the heat associated with the formation of 100.0 g of carbon
natali 33 [55]

Answer:

The right solution is "-602.69 KJ heat".

Explanation:

According to the question,

The 100.0 g of carbon dioxide:

= \frac{100.0 \ g}{114.33\  g/mole}

= 0.8747 \ moles

We know that 16 moles of CO_2 formation associates with -11018 kJ of heat, then

0.8747 moles CO_2 formation associates with,

= -\frac{0.8747}{16}\times 11018 \ KJ \ of \ heat

= -0.0547\times 11018

= -602.69 \ KJ \ heat

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If you are traveling at 60mi/hr, how many meters per second is that equivalent to?
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