Answer:
No they are not the same the are both di
<h3>
Answer:</h3>
251 mol Xe
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 1.51 × 10²⁶ atoms Xe
[Solve] moles Xe
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- [DA] Set up:
![\displaystyle 1.51 \cdot 10^{26} \ atoms \ Xe(\frac{1 \ mol \ Xe}{6.022 \cdot 10^{23} \ atoms \ Xe})](https://tex.z-dn.net/?f=%5Cdisplaystyle%201.51%20%5Ccdot%2010%5E%7B26%7D%20%5C%20atoms%20%5C%20Xe%28%5Cfrac%7B1%20%5C%20mol%20%5C%20Xe%7D%7B6.022%20%5Ccdot%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20Xe%7D%29)
- [DA] Multiply/Divide [Cancel out units]:
![\displaystyle 250.747 \ mol \ Xe](https://tex.z-dn.net/?f=%5Cdisplaystyle%20250.747%20%5C%20mol%20%5C%20Xe)
<u>Step 4: Check</u>
<em>Follow sig fig rule and round. We are given 3 sig figs.</em>
250.747 mol Xe ≈ 251 mol Xe
Answer is: the molarity of a solution of HF is 0.73 M.
n(HF) = 4.400 mol; amount of hydrofluoric acid.
V(HF) = 6.00 l; volume of hydrofluoric acid.
c(HF) = n(HF) ÷ V(HF).
c(HF) = 4.400 mol ÷ 6.00 l.
c(HF) = 0.733 mol/l; molarity of a solution (hydrofluoric acid).