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aleksandrvk [35]
3 years ago
10

What is a substance that reduces the amount of activation energy in a chemical reaction called?

Chemistry
2 answers:
astraxan [27]3 years ago
5 0

Answer: Catalyst

Explanation: Catalyst is a substance which enhances the speed of Chemical reaction without consuming in the Reaction and it is regenerated after completion of Reaction and it is reused further cycle of reaction.

So catalyst reduces the activation energy by speed up the reaction

FinnZ [79.3K]3 years ago
3 0

The answer is catalyst

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An electrochemical cell has the following standard cell notation.
Alona [7]

Explanation:

The given following standard cell notation.  

Mg(s) | Mg^2+ (aq) || Aq^+(aq) | Aq(s)

Oxidation:

Mg(s)\rightarrow Mg^{2+}+2e^-....(1)

Magnesium metal by loosing 2 electrons is getting converted into magnesium cation. Hence, getting oxidized

Reduction:

Ag^+(aq)+1e^-\rightarrow Ag(s)...(2)

Silver ion by gaining 1 electrons is getting converted into silver metal. Hence, getting reduced.

Overall redox reaction: (1)+2 × (2)

Mg(s)+2Ag^+(aq)\rightarrow Mg^{2+}+2Ag(s)

4 0
3 years ago
Walter was heating some cubes of ice while conducting an experiment. At one point, the ice melted into water. What is the correc
tatiyna
This would be the Melting point because it is showing that at a certain heat it melts so therefore it is the point it melts and therefore called the melting point
7 0
3 years ago
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Before a Bill can move to "floor consideration" in the General Assembly, it must first pass through
ANEK [815]

Answer:I believe it is the Senate

Explanation:

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3 years ago
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Calculate the molarity of a kcl solution prepared by dissolving 0.898 moles of kcl in 250. ml of water
prohojiy [21]
  the molarity  of KCl  solution prepared by dissolving 0.898 mole of KCl in 250 ml water  is calculated using the below  formula

 molarity= moles/volume in liters

moles= 0.898 moles
volume in liters= 250/1000 =0.25 liters

molarity is therefore= 0.898/0.25= 3.592 M
3 0
3 years ago
The half-life of cesium-137 is 30 years. Suppose we have a 150 mg sample. (a) Find the mass (in mg) that remains after t years.
11Alexandr11 [23.1K]

The half-life of cesium-137 is 30 years. Suppose we have a 150 mg sample. The masses (in mg) that remains after t years A=150/2^t/30yrs

<h3>what do you mean by half-life?</h3>

A substance's half-life is the amount of time it takes for half of it to decompose.

<h3>What is a half-life example?</h3>

Half-life is the length of time it takes for half of an unstable nucleus to go through its decay process. A radioactive element's half-life decay time varies depending on the element. For instance, carbon-10 has a half-life of only 19 seconds, making it impossible to discover in nature. On the other hand, uranium-233 has a half-life of almost 160000 years.

When n half-lives have passed, the formula for estimating the amount still left is:-

A=A°/2^n

where,

A=initial amount

A°=remaining amount

n=t/t_{1/2}

A=150/2^t/30yrs

Learn more about half-life here:-

brainly.com/question/28001741

#SPJ1

4 0
2 years ago
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