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3 years ago

It’s is the same one from my recent ones

Chemistry

1 answer:

UkoKoshka [18]3 years ago

5 0

<h2>9. Given : P + O2 = P2O5</h2>

Balanced Chemical Equation: <u>4</u>P + <u>5</u>O2 = <u>2</u>P2O5

<u>Reactant Product</u>

P = (1) 4 | P = (2) 4

O = (2) 10 | O = (5) 10

Reaction Information

Phosphorus + Dioxygen = <u>Phosphorus Pentoxide</u>

Reaction Type: <u>Synthesis</u>

<h2>10. Given: HCl + NaOH = NaCl + H2O </h2>

<u>Reactant Product</u>

H = 2 | H = 2

Cl = 1 | Cl = 1

Na = 1 | Na = 1

O = 1 | O = 1

<h3>Chemical Equation is already in balance.</h3>

Reaction Information<em>:</em><em> </em><em>Hydrogen Chloride </em>+ <em>Sodium Hydroxide</em> = <em>Sodium Chloride </em>+ <em>Water</em>

Reaction Type<u> </u><u>:</u><u> </u><u>Double Displacement (Acid-Base)</u>

<u>How to balance chemical equation?</u>

brainly.com/question/15939935

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Answer:

P = 1/8

Explanation:

The wave function of a particle in a one-dimensional box is given by:

$\psi = \sqrt \frac{2}{L} sin(\frac{n \pi x}{L})$

Hence, the probability of finding the particle in the one-dimensional box is:

$P = \int_{x_{1}}^{x_{2}} \psi^{2} dx$

$P = \int_{x_{1}}^{x_{2}} (\sqrt \frac{2}{L} sin(\frac{n \pi x}{L}))^{2} dx$

$P = \frac{2}{L} \int_{x_{1}}^{x_{2}} (sin^{2}(\frac{n \pi x}{L}) dx$

Evaluating the above integral from x₁ = 0 to x₂ = L/8 and solving it, we have:

$P = \frac{2}{L} [\frac{L}{16} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})]$

$P = \frac{1}{8} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})$

Solving for n=4:

$P = \frac{1}{8} (1 - 4\frac{sin(\frac{4 \pi}{4})}{4 \pi})$

$P = \frac{1}{8} (1 - \frac{sin (\pi)}{\pi})$

$P = \frac{1}{8}$

I hope it helps you!

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2 years ago

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Veseljchak [2.6K]

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