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gladu [14]
3 years ago
9

It’s is the same one from my recent ones

Chemistry
1 answer:
UkoKoshka [18]3 years ago
5 0
<h2>9. Given : P + O2 = P2O5</h2>

Balanced Chemical Equation: <u>4</u>P + <u>5</u>O2 = <u>2</u>P2O5

<u>Reactant Product</u>

P = (1) 4 | P = (2) 4

O = (2) 10 | O = (5) 10

Reaction Information

Phosphorus + Dioxygen = <u>Phosphorus Pentoxide</u>

Reaction Type: <u>Synthesis</u>

<h2>10. Given: HCl + NaOH = NaCl + H2O </h2>

<u>Reactant Product</u>

H = 2 | H = 2

Cl = 1 | Cl = 1

Na = 1 | Na = 1

O = 1 | O = 1

<h3>Chemical Equation is already in balance.</h3>

Reaction Information<em>:</em><em> </em><em>Hydrogen Chloride </em>+ <em>Sodium Hydroxide</em> = <em>Sodium Chloride </em>+ <em>Water</em>

Reaction Type<u> </u><u>:</u><u> </u><u>Double Displacement (Acid-Base)</u>

<h3>For more info:</h3>

<u>How to balance chemical equation?</u>

brainly.com/question/15939935

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marta [7]

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3 0
2 years ago
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a scientist uses 68 grams of CaCo3 to prepare 1.5 liters of solution. what is the molarity of this solution?
victus00 [196]

Answer: 0.4533mol/L

Explanation:

Molar Mass of CaCO3 = 40+12+(16x3) = 40+12+48 = 100g/mol

68g of CaCO3 dissolves in 1.5L of solution.

Xg of CaCO3 will dissolve in 1L i.e

Xg of CaCO3 = 68/1.5 = 45.33g/L

Molarity = Mass conc.(g/L) / molar Mass

Molarity = 45.33/100 = 0.4533mol/L

7 0
3 years ago
What happens when a solid is dissolved in a liquid
slava [35]

the solid particles take up the intermolecular spaces in the liquid.

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What phase will you see one week after
slava [35]

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yes.

Explanation:

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This type of fatty acid has at least one double bond in the carbon-to-carbon chain and also contains protective qualities
Sloan [31]
There are two general classifications of fatty acids according to their structure: saturated and unsaturated fatty acids. Unsaturated fatty acids are those that contain at least one of either a double or triple bond. Therefore, the answer to this questions is: unsaturated fatty acid. Its function is to protect the organs as a cushion, or as storage area for excess energy.
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