Answer:
The instantaneous velocity of the rocket the moment before it hits the ground is 50 m/s.
Explanation:
Given;
initial velocity of the rocket, u = 50 m/s
Determine the maximum height reached by the rocket.
at maximum height reached by the rocket, the final velocity, v = 0
v² = u² -2gh
0 = 50² - 2(9.8)h
19.6h = 2500
h = 2500 / 19.6
h = 127.55 m
At maximum height, the time to reach ground is given by;
h = ¹/₂gt²
Before the rocket hits the ground the final velocity will be maximum;
v = u + gt
v = 0 + 9.8 x 5.1
v = 50 m/s
Therefore, the instantaneous velocity of the rocket the moment before it hits the ground is 50 m/s.
Answer:
C) 1200 rpm
Explanation:
= Diameter of bigger pulley = 24 inch
= Diameter of smaller pulley = 8 inch
= Speed of bigger pulley = 400 rpm
= Speed of smaller pulley
The relation between revolutions per minute and diameter is that they are inversely proportional.
The number of revolutions per minute of the smaller pulley is 1200 rpm
Answer:
Explanation:
a. Given that:
mass of first & second piece,
mass of 3rd piece,
-velocity of first piece(
) and
as velocity of 2nd piece (
)
Let be velocity of 3rd piece=?
#Vessel is at rest before explosion. Considering conservation of linear momentum:
#Dividing both sides by
#Plug the values:
#So the magnitude of the third piece is:
Magnitude of the 3rd piece is 10.84 m/s
b. To find direction of the magnitude (as an angle relative to the -axis), we find
. The angle is obtained by getting the tan inverse as:
-The direction of the magnitude (angle relative to the x-axis) is 45°