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Ronch [10]
3 years ago
13

A space-walking astronaut has become detached from her spaceship. She's floating in space while holding a wrench. She is thinkin

g about how she might get back to the ship, which she can see 50 m from her current location. Which of Newton's three laws will help her the most to get back to the ship?
Physics
1 answer:
ser-zykov [4K]3 years ago
6 0

Answer:

please find the solution which is defined as follows:

Explanation:

Throughout the opposite direction, she not able to throw her tool-belt. In this scenario, she will be sending her floating through her ship. Unless interrupted, it could refer to Newton's The rule of it in motion remains in motion. Consequently, if they throw it one way because there are no molecules to interrupt your course, you can continue to go the other way.

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A straight fin is made from copper (k = 388 W/m-K) and is 0.5 cm in diameter and 30 cm long. The temperature at the base of the
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Answer:

The rate of transfer of heat is 0.119 W

Solution:

As per the question:

Diameter of the fin, D = 0.5 cm = 0.005 m

Length of the fin, l =30 cm = 0.3 m

Base temperature, T_{b} = 75^{\circ}C

Air temperature, T_{infty} = 20^{\circ}

k = 388 W/mK

h = 20\ W/m^{2}K

Now,

Perimeter of the fin, p = \pi D = 0.005\pi \ m

Cross-sectional area of the fin, A = \frac{\pi}{4}D^{2}

A = \frac{\pi}{4}(0.5\times 10^{-2})^{2} = 6.25\times 10^{- 6}\pi \ m^{2}

To calculate the heat transfer rate:

Q_{f} = \sqrt{hkpA}tanh(ml)(T_{b} - T_{infty})

where

m = \sqrt{\frac{hp}{kA}} = \sqrt{\frac{20\times 0.005\pi}{388\times 6.25\times 10^{- 6}\pi}} = 41.237

Now,

Q_{f} = \sqrt{20\times 388\times 0.005\pi\times 6.25\times 10^{- 6}\pi}tanh(41.237\times 0.3)(75 - 20) = 0.119\ W

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Read 2 more answers
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