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Ronch [10]
3 years ago
13

A space-walking astronaut has become detached from her spaceship. She's floating in space while holding a wrench. She is thinkin

g about how she might get back to the ship, which she can see 50 m from her current location. Which of Newton's three laws will help her the most to get back to the ship?
Physics
1 answer:
ser-zykov [4K]3 years ago
6 0

Answer:

please find the solution which is defined as follows:

Explanation:

Throughout the opposite direction, she not able to throw her tool-belt. In this scenario, she will be sending her floating through her ship. Unless interrupted, it could refer to Newton's The rule of it in motion remains in motion. Consequently, if they throw it one way because there are no molecules to interrupt your course, you can continue to go the other way.

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Many organ system serve to help maintain a healthy body. The excretory system is an organ system which is composed of all sweat
Cerrena [4.2K]

Answer: D

Explanation:

Cause removing excess waste from the body helps to maintain a steady health

3 0
3 years ago
a stone is dropped from the top of 50 m high tower simultaneously another stone is thrown upward with a speed of 20 m/s . calcul
Darina [25.2K]
'H' = height at any time
'T' = time after both actions
'G' = acceleration of gravity
'S' = speed at the beginning of time
Let's call 'up' the positive direction.
Let's assume that the tossed stone is tossed from the ground, not from the tower.

For the stone dropped from the 50m tower:

H = +50 - (1/2) G T²

For the stone tossed upward from the ground:

H = +20T - (1/2) G T²

When the stones' paths cross, their <em>H</em>eights are equal.

50 - (1/2) G T² = 20T - (1/2) G T²

Wow !  Look at that !  Add (1/2) G T² to each side of that equation,
and all we have left is:

50 = 20T  Isn't that incredible ? ! ?

Divide each side by 20 :

<u>2.5 = T</u>

The stones meet in the air 2.5 seconds after the drop/toss.

I want to see something: 
What is their height, and what is the tossed stone doing, when they meet ?

Their height is  +50 - (1/2) G T² = 19.375 meters

The speed of the tossed stone is  +20 - (1/2) G T = +7.75 m/s ... still moving up.
I wanted to see whether the tossed stone had reached the peak of the toss,
and was falling when the dropped stone overtook it.  The answer is no ... the
dropped stone was still moving up at 7.75 m/s when it met the dropped one.
7 0
3 years ago
A grey hound can run about 40/mph is it velocity,acceleration, or speed
loris [4]

Answer: Speed

Explanation:

Speed is the time it takes something to travel a certain distance. Accelaration is the rate at which an object's speed changes. Velocity is a vector of the object's speed and direction.

5 0
3 years ago
The greatest height reported for a jump into an airbag is 99.4 m by stuntman Dan Koko. In 1948 he jumped from rest from the top
vaieri [72.5K]

Answer:

v = 44,16 m/s

Explanation:

We will fixate our reference in the starting point from where Dan jumped of, at the top of the Casino. Therefore, the displacement made when dan reached the airbag would be of y= -99,4 m viewed from our reference. We describe the motion of dan with the equation:

v_y^2 =v_0^2 +2ay

Dan jumped from the rest, that means that the initial velocity v_0=0, therefore:

 v_y^2 =2ay \rightarrow v_y = \sqrt{2ay}

Since Dan is moving in the negative axis regarding our reference point, we take the negative root of the equation.

v_y=-√(2*(-9,81 m/s^2 )*(-99,4 m) )=44,1613 m/s  v_y =- \sqrt{2*(-9,81 m/s^2)*(-99,4 m)} = 44,1613 m

So, if we don’t take the air resistance into account, Dan would have achieved an velocity of 44,16 m/s when he reached the airbag.

I hope everything was clear with my explanation. If you need anything else, let me know. Have a great day :D

7 0
3 years ago
Sixty identical drippers, each with a hole of diameter 1.00 mm, are used to water a yard. If the water in the main pipe of diame
VashaNatasha [74]

Answer:

a

   V =  5.30 *10^{-2} \ m^3

b

   v_1 = 0.3127 \ m/s

Explanation:

From the question we are told that

   The number of identical drippers is  n =  60

   The diameter of each hole in each dripper is  d =  1.0 \  mm =  0.001 \  m  

   The diameter of the main pipe is  d_m  =  2.5 \  cm  =  0.025 \  m

    The speed at which the water is flowing is  v  =  3.00 \  cm/s =  0.03 \  m/s

Generally the amount of water used in  one hour = 3600 seconds is mathematically represented as

          V =  A *  v  *  3600

Here A is the area of the main pipe with value

         A =  \pi  * \frac{d^2}{4}

=>       A = 3.142   * \frac{0.025^2}{4}

=>        A =  0.0004909 \  m^2

So  

=>   V =  0.0004909  *  0.03  *  3600

=>  V =  5.30 *10^{-2} \ m^3

Generally the area of the drippers is mathematically represented as

       A_1=  n  * \pi \frac{d^2}{4}

=>    A_1 =  60   * 3.142 *  \frac{0.001 ^2}{4}

=>    A_1 =  4.713 *10^{-5} \  m^2

Generally from continuity equation we have that  

         Av =  A_1 v_1

=>      0.0004909 *  0.03 =  4.713 *10^{-5} *  v_1

=>   v_1 = 0.3127 \ m/s

   

     

3 0
3 years ago
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