Answer:
a) 6.4 kJ
b) 43.4 kJ
Explanation:
a)
= Heat absorbed = 37 kJ
= Coefficient of performance = 5.8
= Work done
Heat absorbed is given as
=
37 = (5.8)
= 6.4 kJ
b)
= work per cycle required
= +
= 37 + 6.4
= 43.4 kJ
Answer:
La fuerza que será necesaria aplicar a un cuerpo de 20kg de masa para imprimirle una aceleración a=4m/s² es 80 N.
Explanation:
La segunda ley de Newton, llamada ley fundamental o principio fundamental de la dinámica, plantea que un cuerpo se acelera si se le aplica una fuerza.
De esta manera, esta ley establece que las aceleraciones que experimenta un cuerpo son proporcionales a las fuerzas que recibe. Dicho de otra forma, la aceleración de un cuerpo es proporcional a la fuerza neta que se le aplica. Cuanto mayor es la fuerza que se le aplica a un objeto con una masa dada, mayor será su aceleración.
La segunda Ley de Newton se expresa matemáticamente como:
F = m*a
Donde:
-
F es la fuerza neta. Se expresa en Newton (N)
- m es la masa del cuerpo. Se expresa en kilogramos (Kg.).
- a es la aceleración que adquiere el cuerpo. Se expresa en metros sobre segundo al cuadrado (m/s²).
En este caso:
Reemplazando:
F= 20 kg* 4 m/s²
Resolviendo:
F= 80 N
<u><em>La fuerza que será necesaria aplicar a un cuerpo de 20kg de masa para imprimirle una aceleración a=4m/s² es 80 N.</em></u>
Answer:
d = 142.5 m
Explanation:
This is a vector exercise. Let's calculate how much the boat travels in the 40s
d₀ = 
t
d₀ = 0.75 40
d₀ = 30 m
Let's write the kinematic equations
Boat
x = d₀ + t
x = 0 + 
t
At the meeting point the coordinate is the same for both
d₀ + t = t
t ( - ) = d₀
t = d₀ / ( - )
The two go in the same direction therefore the speeds have the same sign
t = 30 / (0.95-0.775)
t = 150 s
The distance traveled by man is
d = t
d = 0.95 150
d = 142.5 m
Answer:
The ratio of the translational rms speed in the ionosphere to the translational rms near the earth's surface is 
Explanation:
The relation between the translational rms speed and the temperature is given by :
So, 
When the temperature is three times greater.
The ratio of the translational rms speed in the ionosphere to the translational rms near the earth's surface is :
Hence, this is the required solution.
Answer:
The average speed on the second leg of the trip is 2 m/s
Explanation:
Notice that the second leg of the trip is from 8 m in the horizontal axis heading to the left to position 4 m. So the velocity is going to be negative and given by the quotient of the change in position (-4 m) divided by the time it took: 2 seconds.
This gives: -4/ 2 m/s = -2 m/s
But the speed is going to be the absolute value of the velocity, that is:
2 m/s
