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Mashcka [7]
3 years ago
8

What are the respective concentrations (moles/liter) of k+ and po43- afforded by dissolving 0.800 mol k3po4 in water and dilutin

g to 1.63l?
Chemistry
1 answer:
Kitty [74]3 years ago
8 0

<em>Answer: </em>

  •                      Concentration of K+  = 1.47 M
  •                      Concentration of Po4∧-2 = 0.4908 M

<em>Given Data:</em>

   No. of moles of K3PO4 = 0.800 mole

  Molarity of K3PO4 =  0.800÷1.63 = 0.4908

<em>Chemical equations:</em>

        K3PO4 ⇔3 K+   +  PO4∧-2

<em>Solution: </em>

         K3PO4 : K+                                                K3PO4 : PO4∧-2

            1  :    3                                                            1      :    1

        0.4908 = 0.4908 × 3 = 1.47 M                   0.4908 = 0.4908 × 1 = 0.4908 M

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What is Boyle's law ?

Boyle's law, also known as Mariotte's law, is a relationship describing how a gas will compress and expand at a constant temperature. The pressure (p) of a given quantity of gas changes inversely with its volume (v) at constant temperature, according to this empirical connection, which was established by the physicist Robert Boyle in 1662. In equation form, this means that pv = k, a constant.

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