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umka2103 [35]
4 years ago
8

What power rating of resistors would you use in the application required it to handle 0.6W?

Physics
1 answer:
aliya0001 [1]3 years ago
5 0

I would use a resistor rated for 1 W or more. Not less.

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What can be concluded about the spread of the histogram? A histogram titled Maria's Monthly Jogging has miles run on the x-axis
Aleonysh [2.5K]

Answer:

I think it is A

Explanation:

l

8 0
3 years ago
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ERCRSOVOS - Table tennis footwork that is useful in this moment to cover a large distance quickly (SCRAMBLED)PE)
nata0808 [166]

Answer:

it's CROSSOVER I knew it because I'm a table tennis player

4 0
3 years ago
The electron in a ground-state h atom absorbs a photon of wavelength 97. 25 nm. to what energy level does the electron move?
Alecsey [184]

The electron in a ground-state H atom absorbs a photon of wavelength 97. 25 nm.  Energy level till where the electron move is 4

Rydberg's equation is formula which signifies relation of wavelength of incident photon and the energy level.

Rydberg's equation is used to find out the relation between the wavelength and the Energy Levels:

1/λ = RZ² (1/n₁² - 1/n₂²)

where, λ is wavelength = 97.25 nm

           R is the Rydberg constant = 1.0967 × 10⁷ m

           n₁ is the initial energy level i.e. the Ground state, n₁  = 1

           n₂ is the higher energy level

On substitution of the above value:

1/97.25 × 10⁻⁹ = 1.0967 × 10⁷ ( 1 -  1/n₂²)

On solving,

⇒ n₂ = 4

Hence, the higher energy level is 4

Learn more about Energy Level here, brainly.com/question/17396431

#SPJ4

5 0
2 years ago
The low areas created as a sound wave propagates are called rarefactions
qwelly [4]

The answer is; pressure

The sound is a longitudinal wave meaning the particles vibrate parallel to the direction of the wave. Sound waves, therefore, produce compression (akin to the crest in a transverse wave) and rarefaction regions (akin to a trough in a transverse wave) as its energy is propagated in the medium.  


8 0
4 years ago
Read 2 more answers
Which of the following statements are true for electric field lines? Check all that apply. Check all that apply. Electric field
Scilla [17]

Answer:

Electric field lines point away from positive charges and toward negative charges. <u>True</u>

Electric field lines are continuous; they do not have a beginning or an ending.<u> False</u>

Electric field lines can never intersect. <u>True</u>

Electric field lines are close together in regions of space where the magnitude the electric field is weak and are father apart where it is strong. <u>False</u>

At every point in space, the electric field vector at that point is tangent to the electric field line through that point.<u> True</u>

Explanation:

Electric field lines point away from positive charges and toward negative charges. Always the field lines go to negative charges and leave from positive charges.

Electric field lines are continuous; they do not have a beginning or an ending.<u> False  </u>

Because the field lines starts at positive charges and ends in negative charges.

Electric field lines can never intersect. <u>True</u>

It can not intercept the field lines because in that point the the field would have two directions. Besides, in that point the real value of the field should be found adding both field lines.

Electric field lines are close together in regions of space where the magnitude the electric field is weak and are father apart where it is strong. <u>False</u>

This fact is opposite to that so the regions of space where the magnitude the electric field is weak the lines are father apart and where the field is strong  the lines are close together.

At every point in space, the electric field vector at that point is tangent to the electric field line through that point.<u> True</u>

This statement correspond to the definition of the field line.

5 0
3 years ago
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