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rosijanka [135]
3 years ago
15

What is shown in the diagram

Physics
2 answers:
beks73 [17]3 years ago
8 0
I would have to say that the answer is D.) an electromagnet 
tigry1 [53]3 years ago
4 0
The answer is: Electromagnet.  
Electromagnets are magnets that are powered by a battery. You can usually find them in generators. 
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An object moves in a circular path at a constant speed. what is the direction of the net force acting on the object?
mr Goodwill [35]
In a circular motion im pretty sure
6 0
4 years ago
According to American Heart Association, your target heart rate is__________.
sladkih [1.3K]

Answer:

B

Explanation:

A normal heart rate is from 85-95% the other heart rate is not normal because your heart is beating more than normal

4 0
3 years ago
A mountain climber packs too much gear and finds it difficult to reach the summit before a storm blows in. How does this scenari
MissTica

As the climber climbs the mountain, he needs to over his or her own weight component along the slope of the mountains.

By Newton's second law: Net force = Mass x acceleration

Hence, greater the mass, greater will be the force required to move up the mountain. Hence, the climber will need to apply higher force to climb up as he or she has packed too much, which resulted in the increase in the mass. Hence, there is a increase in the force which will pull him or her downward.

5 0
3 years ago
Read 2 more answers
b. A string is wrapped around a pulley of radius 0.05 m and moment of inertia 0.2 kg  m2. If the string is pulled with a force
Oduvanchick [21]

Answer:

f = 8 N

Explanation:

Data provided in the question

Radius of the pulley  = r = 0.05 m

Moment of inertia = (I) = 0.2 kg.m^{2}

Angular acceleration = ∝ = 2 rad/sec

Based on the above information

As we know that

Torque is

= force \times  radius

= f \times r

And,

Torque is also

= moment\ of\ inertia \times angular\ acceleration

= I \times \alpha

So,

We can say that

f \times r = I \times \alpha

f \times 0.05 = 0.2 \times 2

0.05f = 0.4

f = 8 N

We simply applied the above formulas

8 0
4 years ago
A car of weight 2000 Newtons (N) moves horizontally with an acceleration of 3.3 meters/second square. What is the Force acting o
Nadya [2.5K]

Explanation:

Mass of the car = 2000N / 10 = 200kg.

Fnet = ma. Assuming there is only the horizontal force acting on the car, then

F = (200kg)(3.3m/s²) = 660N.

5 0
3 years ago
Read 2 more answers
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