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allsm [11]
3 years ago
9

A system executes a power cycle while receiving 1000 kJ by heat transfer at a temperature of 500 K and discharging 700 kJ by hea

t transfer at a temperature of 300 K. There are no other heat transfers. Determine the cycle efficiency. Use the Clausius Inequality to determine , in kJ/K. Determine if this cycle is internally reversible, irreversible, or impossible.
Engineering
1 answer:
Ghella [55]3 years ago
8 0

Answer:

\eta_{th} = 30\,\%, \eta_{th,max} = 40\,\%, \Delta S = \frac{1}{3}\,\frac{kJ}{K}, The cycle is irreversible.

Explanation:

The real cycle efficiency is:

\eta_{th} = \frac{1000\,kJ-700\,kJ}{1000\,kJ} \times 100\,\%

\eta_{th} = 30\,\%

The theoretical cycle efficiency is:

\eta_{th,max} = \frac{500\,K-300\,K}{500\,K} \times 100\,\%

\eta_{th,max} = 40\,\%

The reversible and real versions of the power cycle are described by the Clausius Inequalty:

Reversible Unit

\frac{1000\,kJ - 600kJ}{300\,K}= 0

Real Unit

\Delta S = \frac{1000\,kJ-600\,kJ}{300\,K} -\frac{1000\,kJ-700\,kJ}{300\,K}

\Delta S = \frac{1}{3}\,\frac{kJ}{K}

The cycle is irreversible.

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3 years ago
If a hoist lifts a 4500lb load 30ft in 15s, the power delivered to the load is a) 18.00hp b) 9000hp c) 16.36hp d) None of the ab
12345 [234]

Answer:

Explanation:

load = 4500lb                   lift height= 30 ft

time =15 s

velocity=\frac{30}{15} ft/s

velocity=2 ft/s

power = force\times velocity

power={4500}\times2

power= 9000 lb ft/s

1 hp= 550 lb ft/s

power= \frac{9000}{550} =16.36 hp

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4 0
3 years ago
A reservoir delivers water to a horizontal pipeline 39 long The first 15 m has a diameter of 50 mm, after which it suddenly beco
allsm [11]

Answer:

The difference of head in the level of reservoir is 0.23 m.

Explanation:

For pipe 1

d_1=50 mm,f_1=0.0048

For pipe 2

d_2=75 mm,f_2=0.0058

Q=2.8 l/s

Q=2.8\times 10^{-3]

We know that Q=AV

Q=A_1V_1=A_2V_2

A_1=1.95\times 10^{-3}m^2

A_2=4.38\times 10^{-3} m^2

So V_2=0.63 m/s,V_1=1.43 m/s

head loss (h)

h=\dfrac{f_1L_1V_1^2}{2gd_1}+\dfrac{f_2L_2V_2^2}{2gd_2}+0.5\dfrac{V_1^2}{2g}

Now putting the all values

h=\dfrac{0.0048\times 15\times 1.43^2}{2\times 9.81\times 0.05}+\dfrac{0.0058\times 24\times 0.63^2}{2\times 9.81\times 0.075}+0.5\dfrac{1.43^2}{2\times 9.81}

So h=0.23 m

So the difference of head in the level of reservoir is 0.23 m.

8 0
3 years ago
I'm a grandma my Samuel needs to be tough in math what do I do
Sedbober [7]
Well you could always do what Hispanics do and repeat the question 2-3 times while yelling till they finally answer
7 0
3 years ago
Read 2 more answers
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