1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tema [17]
3 years ago
14

Energy levels tell us how many _______ there are in an atom. ​

Chemistry
1 answer:
steposvetlana [31]3 years ago
8 0

Answer:

Energy levels tell us how many <u>electrons </u>there are in an atom. ​

Hope this helps!

You might be interested in
A salt is formed when an acld and _____ react.<br>A.Water<br>B.another acid<br>C.base.​
Dovator [93]
Acid and base forms salts
4 0
3 years ago
What is <br> 78.432 miles x 322.3 miles
Phoenix [80]
That would be 25,270.7904 miles
8 0
3 years ago
Helpppp me please please
kipiarov [429]
The answer is letter d    
3 0
3 years ago
Read 2 more answers
The dissociation of calcium carbonate has an equilibrium constant of Kp= 1.20 at 800°C. CaCO3(s) ⇋ CaO(s) + CO2(g)
Fed [463]

Explanation:

(a)   Formula that shows relation between K_{c} and K_{p} is as follows.

                 K_c = K_p \times (RT)^{-\Delta n}

Here, \Delta n = 1

Putting the given values into the above formula as follows.

        K_c = K_p \times (RT)^{-\Delta n}

                  = 1.20 \times (RT)^{-1}

                  = \frac{1.20}{0.0820 \times 1073}

                  = 0.01316

(b) As the given reaction equation is as follows.

               CaCO_{3}(s) \rightleftharpoons CaO(s) + CO_{2}(g)

As there is only one gas so ,

                p[CO_{2}] = K_{p} = 1.20

Therefore, pressure of CO_{2} in the container is 1.20.

(c)   Now, expression for K_{c} for the given reaction equation is as follows.  

             K_{c} = \frac{[CaO][CO_{2}]}{[CaCO_{3}]}

                        = \frac{x \times x}{(a - x)}

                        = \frac{x^{2}}{(a - x)}[/tex]

where,    a = initial conc. of CaCO_{3}

                  = \frac{22.5}{100} \times 9.56

                  = 0.023 M

          0.0131 = \frac{x^{2}}{0.023 - x}

                  x = 0.017

Therefore, calculate the percentage of calcium carbonate remained as follows.

       % of CaCO_{3} remained = (\frac{0.017}{0.023}) \times 100

                                  = 75.46%

Thus, the percentage of calcium carbonate remained is 75.46%.

3 0
4 years ago
Who dis who dis who dis​
Nataliya [291]

Actually when you look that up.... UH that is hair loss or he could be considered MR. CLEAN

3 0
3 years ago
Read 2 more answers
Other questions:
  • Plz help me out ASAP!!
    14·2 answers
  • What is the range of the pH scale?
    6·1 answer
  • Betsy drives at 10 m/s on an entrance ramp and enters a highway where she increases her speed to 24 m/s in only 3 seconds. What
    14·1 answer
  • A sample of oxygen gas has a volume of 45.8 mL when its pressure is 0.492 atm. What
    5·2 answers
  • Which of the following is not an indication of chemical change ?
    10·1 answer
  • What is carbon in the lithosphere initially a part of before part of the burning of fossil fuel?
    11·2 answers
  • Molecules that are loosely packed and move over and around each other are found in
    12·2 answers
  • 2. What volume of a 1.60 mol/L stock solution of calcium chloride would you use to make a 530 mL of a
    6·1 answer
  • Deviation will occur for volume assumption at ____________
    6·2 answers
  • The chemical equation S + 02 - S02 is an example of which type of reaction?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!