Answer:
Explanation:
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Unfortunately, the question is not given in the question; however, it is possible for us to compute the equilibrium constant as the problem is providing the concentrations at equilibrium. Thus, we first set up the equilibrium expression as products/reactants:
![K=\frac{[NO_2]^2}{[NO]^2[O_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BNO_2%5D%5E2%7D%7B%5BNO%5D%5E2%5BO_2%5D%7D)
Then, we plug in the concentrations at equilibrium to obtain the equilibrium constant as follows:
In addition, we can infer this is a reaction that predominantly tends to the product (NO2) as K>>>>1.
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Answer:
So, H2O means two atoms of hydrogen mixed with one atom of oxygen. All pure water is the same, two parts hydrogen to one part oxygen. ... Water cannot be separated by any physical means.
Explanation:
Logic and my notes from chem....
Answer:
See below.
Explanation:
<h3>CoSO4 + Pb(NO3) 2 = Co(NO3) 2 + PbSO4</h3>
Reduction reactions are those reactions that reduce the oxidation number of a substance. Hence, the product side of the reaction must contain excess electrons. The opposite is true for oxidation reactions. When you want to determine the potential difference expressed in volts between the cathode and anode, the equation would be: E,reduction - E,oxidation.
To cancel out the electrons, the e- in the reactions must be in opposite sides. To do this, you reverse the equation with the negative E0, then replacing it with the opposite sign.
Pb(s) --> Pb2+ +2e- E0 = +0.13 V
Ag+ + e- ---> Ag E0 = +0.80 V
Adding up the E0's would yield an overall electric cell potential of +0.93 V.
Answer:-
Ca-Cl
Explanation:-
The more the difference in electronegativity more the polar bond.
In case of Ca-Cl the difference = 3.16 - 1= 2.16
It is more than all the other combinations given.
Hence Ca-Cl is the most polar covalent bond.
