Is Chlorine trifloutide ionic or covalent?

Explain how mixture melting points can be used to distinguish between two compounds

Over [174]

generally melting point of mixture is always different from melting point of pure compound

lets say you have a two compounds called A and B

and you have a unknown compound called X which can be either A or B

now your target is to find unknown is really A or B right?

take some amount of X and mix it with A and B separately

out of these two mixtures one will be pure compound (because we initially assume that unknown can be either A or B)

suppose X + A is same melting with A then X is A

X +B will be less than the melting point of A or

suppose X+B is same melting point like B then X is B

X+A will be less than melting point of B

5 0

2 years ago

Which of these is an oxidation half-reaction?

sweet [91]

Answer:

the answer is Fe + 02 - Fe203

Explanation:

4 0

3 years ago

Helium-oxygen mixtures are used by divers to avoid the bends and are used in medicine to treat some respiratory ailments. What p

frozen [14]

<u>Answer:</u> The mole percentage of helium in the mixture is 64.75 %

<u>Explanation:</u>

To calculate the molar mass of mixture, we use ideal gas equation, which is:

$PV=nRT$

Or,

$P=\frac{m}{M}\frac{RT}{V}$

We know that:

$\text{Density}=\frac{\text{Mass}}{\text{Volume}}$

Rearranging the above equation:

$M=\frac{dRT}{P}$

where,

M = molar mass of mixture = ?

d = density of mixture = 0.538 g/L

R = Gas constant = $62.364\text{ L.mmHg }mol^{-1}K^{-1}$

T = temperature of the mixture = $25^oC=[25+273]K=298K$

P = pressure of the mixture = 721 mmHg

Putting values in above equation, we get:

$M=\frac{0.538g/L\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 298K}{721mmHg}\\\\M=13.87g/mol$

Molar mass of the mixture will be the sum of molar mass of each substance each multiplied by its mole fraction.

Let the mole fraction of Helium be 'x' and that of oxygen be '1-x'

$M=(x\times M_{He})+((1-x)\times M_{O_2})$

We know that:

Molar mass of helium = 4.00 g/mol

Molar mass of oxygen gas = 32g/mol

Putting values in above equation, we get:

$13.87=(x\times 4)+((1-x)\times 32)\\\\x=0.6475$

Mole fraction of helium in the mixture = 0.6475

Calculating the mole percentage of helium in the mixture:

$\text{Mole percentage of helium in the mixture}=x\times 100\\\\\text{Mole percentage of helium in the mixture}=0.6475\times 100=64.75\%$

Hence, the mole percentage of helium in the mixture is 64.75 %

8 0

3 years ago

What important discovery did Ernest Rutherford make?

EleoNora [17]

Answer:

D if im pretty sure

Explanation:

In 1909 he began experiments that were to change the face of physics. He discovered the atomic nucleus and developed a model of the atom that was similar to the solar system.

7 0

2 years ago

Read 2 more answers

An iron ore was found to contain 92.0% pyrite (fool's gold). Pyrite has the formula FeS2and is 46.5% iron. How many grams of iro

Liula [17]

Firstly calculate the grams in the last 8 percent before moving onto the pyrite section.
50.8x0.08=4.064g
We know that iron ore in this case has 92 percent pyrite which contains 46.5 percent iron so we do 50.8x0.92=46.736g from this we need to find 46.5 percent of the iron content in the 92 percent pyrite section then add this answer to the 8 percent of iron ore we found at the start.46.736x0.465=21.73224g
21.73224g+4.064=25.79624g of iron ore 25.8g(3sf)

4 0

3 years ago