Answer:
QPSK: 7.5 MHz
64-QAM:2.5 MHz
64-Walsh-Hadamard: 160 MHz
Explanation:
See attached picture.
The workers went to bed hungry probably because they are hard workers and so didn’t want to eat because they didn’t want to take break┌(; ̄◇ ̄)┘
Answer:
I = 0.625 A
Explanation:
Given that,
Power of the light bulb, P = 75 W
Voltage of the circuit, V = 120 V
We need to find the current flowing through it. We know that, Power is given by :
![P=V\times I](https://tex.z-dn.net/?f=P%3DV%5Ctimes%20I)
I is the electric current
![I=\dfrac{P}{V}\\\\I=\dfrac{75\ W}{120\ V}\\\\I=0.625\ A](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7BP%7D%7BV%7D%5C%5C%5C%5CI%3D%5Cdfrac%7B75%5C%20W%7D%7B120%5C%20V%7D%5C%5C%5C%5CI%3D0.625%5C%20A)
So, the current is 0.625 A.