Answer:
Explanation:
m = Mass of roller coaster = 2000 kg
r = Radius of loop = 24 m
v = Velocity of roller coaster = 18 m/s
g = Acceleration due to gravity =
Normal force at the point will be
The force exerted on the track is .
.Express 3.0x10-4 -1.7x10-6 with proper significant figure.
1 answer:
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I believe this is what you have to do:
The force between a mass M and a point mass m is represented by
So lets compare it to the original force before it doubles, it would just be the exact formula so lets call that F₁
So F₁ = G(Mm/r^2)
Now the distance has doubled so lets account for this in F₂:
F₂ = G(Mm/(2r)^2)
Now square the 2 that gives you four and we can pull that out in front to give
F₂ = G(Mm/r^2)
Now we can replace G(Mm/r^2) with F₁ as that is the value of the force before alterations
now we see that:
F₂ = F₁
So the second force will be 0.25 (1/4) x 1600 or 400 N.
2.5m/s
Explanation:
Given parameters:
Initial velocity = 0m/s
Acceleration = 0.5m/s²
time of travel = 5s
Solution:
Final velocity = ?
Solution:
Acceleration can be defined as the change in velocity with time:
Acceleration =
From the equation above, the unknown is final velocity:
Final velocity - initial velocity = Acceleration x time
since initial velocity = 0
Final velocity = 0.5 x 5 = 2.5m/s
Learn more:
Acceleration brainly.com/question/3820012
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