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tatyana61 [14]
3 years ago
13

Four discs are spinning at constant angular velocity. Four ideantical balls are dropped on the discs at different distances from

the center. The balls are dropped from rest and stick to the disc. Rank the discs in terms of final angular velocity from lowest to highest.
Physics
1 answer:
Arlecino [84]3 years ago
8 0

Answer: They will have equal final angular velocity.

Explanation:

Since the discs starts from rest and rotates about a fixed axis, they are subject to a constant net torque. The work done by the torque during the second revolution is as the work done during the first revolution.

The four disc will turn through equal angles in equal times.

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A Hooke's law spring is compressed 12.0 cm from equilibrium, and the potential energy stored is 72.0 J. What compression (as mea
Anuta_ua [19.1K]

Answer:14.14 cm

Explanation:

Given

Spring Compression x=12 cm

Potential energy Stored in spring=72 J

Suppose k is the spring constant of spring

Potential Energy of spring is given by =\frac{kx^2}{2}

\frac{k(0.12)^2}{2}=72

k(0.12)^2=144

k=10,000 N/m

k=10 kN/m

for 100 J energy

\frac{k(x_0)^2}{2}=100

10\times 10^3\cdot (x_0)^2=200

(x_0)^2=2\times 10^{-2}

x_0=0.1414

x_0=14.14 cm

6 0
3 years ago
The tires of a car make 75 revolutions as the car reduces its speed uniformly from 95 km/hr to 55 km.hr. the tires have a diamet
sveta [45]
<span>95 km/h = 26.39 m/s (95000m/3600 secs) 55 km/h = 15.28 m/s (55000m/3600 secs) 75 revolutions = 75 x 2pi = 471.23 radians radius = 0.80/2 = 0.40m v/r = omega (rad/s) 26.39/0.40 = 65.97 rad/s 15.28/0.40 = 38.20 rad/s s/((vi + vf)/2) = t 471.23 /((65.97 + 38.20)/2) = 9.04 secs (vf - vi)/t = a (38.20 - 65.97)/9.04 = -3.0719 The angular acceleration of the tires = -3.0719 rad/s^2 Time is required for it to stop (0 - 38.20)/ -3.0719 = 12.43 secs How far does it go? 65.97 - 38.20 = 27.77 M</span>
7 0
3 years ago
What is an example of a wave that is not mechanical and how is it different?
vovikov84 [41]

Answer:

light is an example of a wave that is not mechanical .

it is different as it does not need material medium for its propagation

5 0
3 years ago
Two particles, each with charge Q, and a third charge q, are placed at the vertices of an equilateral triangle as shown. The tot
Gelneren [198K]

Answer:

<em>D. The total force on the particle with charge q is perpendicular to the bottom of the triangle.</em>

Explanation:

The image is shown below.

The force on the particle with charge q due to each charge Q = \frac{kQq}{r^{2} }

we designate this force as N

Since the charges form an equilateral triangle, then, the forces due to each particle with charge Q on the particle with charge q act at an angle of 60° below the horizontal x-axis.

Resolving the forces on the particle, we have

for the x-component

N_{x} = N cosine 60° + (-N cosine 60°) = 0

for the y-component

N_{y} = -f sine 60° + (-f sine 60) = -2N sine 60° = -2N(0.866) = -1.732N

The above indicates that there is no resultant force in the x-axis, since it is equal to zero (N_{x} = 0).

The total force is seen to act only in the y-axis, since it only has a y-component equivalent to 1.732 times the force due to each of the Q particles on q.

<em>The total force on the particle with charge q is therefore perpendicular to the bottom of the triangle.</em>

5 0
4 years ago
Plan an experiment to measure the ideal mechanical advantage of a three-hole punch. (a) What materials would you need? (b) What
Vaselesa [24]

Answer:

A) Three hole punch and either a layered plastic or paper

B) Identify the lengths involved  ,

  Length of input arm / length of output arm = L1/ L2

Explanation:

<u>a) Materials involved includes :</u>

Three hole punch and either a layered plastic or paper

Identify the forces acting on the three-hole punch which are Input and output forces

Identify the points where they act

<u>B) procedures involved </u>

The mechanical advantage = output force / input force

step one:  Identify the lengths involved

assuming no friction or relatively small friction \

mechanical advantage can be calculated as : Length of input arm / length of output arm = L1/ L2

7 0
3 years ago
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