The structure of 1-methoxypropane is CH₃-CH₂-CH₂-OCH₃
I will label the carbons A-D from left to right.
A B C D
CH₃-CH₂-CH₂-OCH₃
In a proton NMR spectrum, we are looking at the chemical shifts of each unique hydrogen atom, and the splitting patterns tell us how many hydrogens are attached to the adjacent carbon. Therefore, the signal from the protons on carbon A will be split by the protons on carbon B, and the signal for protons on carbon A will have a splitting pattern equal to n+1, where n = number of hydrogens on the adjacent carbon.
Therefore, for the protons on carbon A, there are two neighbouring protons and these will give a splitting patter of 3 peaks, also known as a triplet.
Protons on carbon A: 2 adjacent protons result in a triplet signal.
Protons on carbon B: 5 adjacent protons result in a sextet signal.
Protons on carbon C: 2 adjacent protons result in a triplet signal.
Protons on carbon D: 0 adjacent protons result in a singlet signal.
Answer 1
Explanation
Because it’s 1
Please give me brainleist. :)
Answer:
2a. If the temperature is increased, the reaction will shift to the right in an attempt to release some of the heat. As the forward reaction loses heat while the reverse would create more heat.
2b. If the pressure is increased, it would shift to the left to counteract the increase in pressure as the left side will have fewer molecules.
2c. If Cl2 is added the reaction will shift to the left in order to remove the stress of the extra Cl2 and favor the production of more reactant.
2d. If PCl3 is removed, the reaction will shift to the right. When part of the equation is removed the reaction learns to adapt to the loss by trying to make more Pcl3 and counteract the effects of losing the PCl3.
3a. The reaction will shift to the right to produce more heat and counter the negative effects of losing the heat.
3b. It will shift to the left to get rid of the excess HCl being produced and form more reactant from the breakdown of the HCl.
3c. It would shift to the right in order to get rid of the excess form products from it.
3d. If pressure is decreased there will be no effect on the shift of the reaction because there is an even amount of moles of gas on each side.
4a. K=[N2O4(g0] / [NO2(g)]2
4b. (Below)
K=[N2O4(g)] / [NO2(g)]2
0.4 / 0.5(2)
0.4/0.25 = 1.6
Keq= 1.6
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