Answer:
Temperature of the air in the balloon = 272°C
Explanation:
Given:
Volume of balloon = 500 m³
Air temperature = 15° C = 273 + 15 = 288 K
Total weight = 290 kg
Density of air = 1.23 kg/m³
Find:
Temperature of the air in the balloon
Computation:
Density of hot air = Density of air - [Total weight / Volume of balloon]
Density of hot air = 1.23 - [290 - 500]
Density of hot air = 0.65 kg/m³
[Density of hot air][Temperature of the air in the balloon] = [Density of air][Air temperature ]
Temperature of the air in the balloon = [(1.23)(288)]/(0.65)
Temperature of the air in the balloon = 544.98
Temperature of the air in the balloon = 545 K
Temperature of the air in the balloon = 545 - 273 = 272°C
Pitch of the sound increases as frequency increases.
choose B pitch
Answer:
0.0173 V
Explanation:
PARAMETERS GIVEN:
Inductance, L = 2 mH = 0.002 H
Time interval, dt = 0.15 s
Change in current, dI = 1.5 - 0.2 = 1.3 A
The magnitude of the induced EMF is given as:
EMF = | -L*dI/dt |
EMF = (0.002 * 1.3) / 0.15
EMF = 0.0173 V
Answer:
Convection is the transfer of thermal energy from one place to another by the movement of gas or liquid particles. How does this happen? As a gas or liquid is heated, the substance expands. This is because the particles in liquids and gases gain kinetic energy when they are heated and start to move faster.
