Explanation:
We know that relation between and is as follows.
= 14
As it is given that is 8.18. Therefore, calculate the value of as follows.
= 14
= 14
= 14 - 8.18
= 5.82
Similarly, as value of pH is given as 7.18. Therefore, value of pOH will be as follows.
pH + pOH = 14
7.18 + pOH = 14
pOH = 6.82
Let us take that B represents the enzyme. Hence, its reaction with proton will be as follows.
(protonated active enzyme)
Hence, pOH =
6.82 = 5.82 +
= 10
Therefore, percentage of active enzyme = % =
% = 90.9%
Thus, we can conclude that 90.9% is the percentage of the enzyme which is active in a buffer at pH 7.18.
The correct answer is A.
B is incorrect because that only applies to nuclear fission.
C is incorrect because it only applies to nuclear fusion.
D is incorrect because energy can be neither created nor destroyed meaning that this statement is physically impossible,
Answer:
2.01 g H₂
Explanation:
The chemical equation for the electrolysis of water is
2 H₂O ⇒ 2 H₂ + O₂
Convert grams of water to moles. The molar mass of water is 18.016 g/mol.
(36 g)/(18.016 g/mol) = 1.998 mol H₂O
Convert moles of water to moles of hydrogen by using the mole ratio. By looking at the chemical equation, you can see that for every 2 moles of water consumed, 2 moles of hydrogen is produced.
(1.998 mol H₂O) × (2 mol H₂/2 mol H₂O) = 1.998 mol H₂
Now that you have moles of hydrogen, you can convert to grams. The molar mass of hydrogen is 1.008 g/mol.
(1.998 mol) × (1.008 g/mol) = 2.01 g H₂
You will produce 2.01 grams of hydrogen
Answer:
Electronic configuration:
Lv = [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁴
Explanation:
Noble gas electronic configuration.
Noble gas electronic configuration is shortest electronic configuration by using the electronic configuration of noble gases.
Electronic configuration:
Lv = [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁴
Lv stands for livermorium.
Its atomic number is 116.
It is the member chalcogen group.
It has four isotopes, all are under goes alpha decay.
It is synthetic element.
It is artificially produced radioactive element.