Answer:
1.60 is the van't Hoff factor for ammonium chloride in X.
Explanation:
...(1)
where,
=Elevation in boiling point =
i = van't Hoff factor
= Freezing point constant
m = molality
1) When 70.4 g of benzamide are dissolved in 850. g of a certain mystery liquid X.
Mass of benzamide = 70.4 g
Molar mass of benzamide = 121 g/mol
i = 1 (organic molecule)
Mass of liquid X = 850 g = 0.850 kg
= Freezing point constant of liquid X= ?
Putting all value in a (1):
2) When 70.4 g of ammonium chloride are dissolved in 850. g of a certain mystery liquid X.
Mass of ammonium chloride= 70.4 g
Molar mass of ammonium chloride = 53.5 g/mol
i = ? (ionic molecule)
Mass of liquid X = 850 g = 0.850 kg
Putting all value in a (1):
i = 1.6011 ≈ 1.60
1.60 is the van't Hoff factor for ammonium chloride in X.