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Nookie1986 [14]
3 years ago
15

The mass defect for the formation of lithium-6 is 0.0343 g/mol. The binding energy for lithium-6 nuclei is ________ kJ/mol. Ente

r your answer in exponential format (sample 1.23E-4) with two decimal places and no units.
Chemistry
1 answer:
Sholpan [36]3 years ago
7 0

<u>Answer:</u> The binding energy for lithium-6 nuclei is 3.09 E+11

<u>Explanation:</u>

Binding energy is defined as the energy which holds the nucleus together. It is basically the product of mass defect and the square of the speed of light.

This energy is calculated by using Einstein's equation, which is:

E=\Delta mc^2

where,

E = Binding energy of the atom

Delta m = Mass defect = 0.0343g/mol = 0.0343\times 10^{-3}kg/mol     (Conversion factor: 1kg=10^3g )

c = speed of light = 3\times 10^8m/s

Putting values in above equation, we get:

E=0.0343\times 10^{-3}kg/mol\times (3\times 10^8m/s)^2

E=3.09\times 10^{14}J/mol=3.09\times 10^{11}kJ/mol     (Conversion factor: 1kJ=10^3J )

Hence, the binding energy for lithium-6 nuclei is 3.09 E+11

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antoniya [11.8K]

C. It has mass and volume

Explanation:

Every atom of an element has mass and volume. Mass is the amount of substance it contains this is usually a function of their subatomic particles.

The bulk of the mass of an atom is concentrated in the nucleus where we have protons and neutrons. Electrons do not really add much to the mass of an atom.

Atoms also have specific volume.

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learn more:

Matter brainly.com/question/8839455

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6 0
3 years ago
A vessel of volume 22.4 dm3 contains 20 mol h2 and 1 mol n2 ad 273.15 k initially. All of the nitrogen reacted with sufficient h
NikAS [45]

Nitrogen combine with hydrogen to produce ammonia \text{NH}_3 at a 1:3:2 ratio:

\text{N}_2 \; (g) + 3 \;  \text{H}_2 \; (g) \leftrightharpoons 2\; \text{NH}_3 \; (g)

Assuming that the reaction has indeed proceeded to completion- with all nitrogen used up as the question has indicated. 3 \; \text{mol} of hydrogen gas would have been consumed while 2 \; \text{mol} of ammonia would have been produced. The final mixture would therefore contain

  • 17 \; \text{mol} of \text{H}_2 \; (g) and
  • 2 \; \text{mol} of \text{NH}_3 \; (g)

Apply the ideal gas law to find the total pressure inside the container and the respective partial pressure of hydrogen and ammonia:

  • \begin{array}{lll} P(\text{container}) &= & n \cdot R \cdot T / V \\ & = & (17 + 2) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=&  1.926 \times 10^{3} \; \text{kPa} \end{array}
  • \begin{array}{lll} P(\text{H}_2) &= & n \cdot R \cdot T / V \\ & = & (17) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=&  1.723 \times 10^{3} \; \text{kPa} \end{array}
  • \begin{array}{lll} P(\text{NH}_3) &= & n \cdot R \cdot T / V \\ & = & (2) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=&  2.037 \times 10^{2} \; \text{kPa} \end{array}
6 0
3 years ago
In a previous problem, the empirical formula of a compound of phosphorus and oxygen was found to be p2o5. experimentation shows
agasfer [191]
The empirical formula for the compound is - P₂O₅
the empirical formula is the simplest ratio of whole numbers of components in a compound.
molecular formula is the actual ratio of components in a compound.
we have to first find the number of empirical units in the molecular formula 
molecular mass - 283.89 g/mol
mass of empirical formula - 283.8 g
number of empirical units - 283.89 g/mol / 283.8 g
number of empirical units - 1.000 
therefore empirical formula = molecular formula 
molecular formula - P₂O₅
3 0
3 years ago
Name the process that changes matter into one or more new substances
Brums [2.3K]
Chemical change or process
6 0
3 years ago
What is the mass of water necessary to generate 11.2 L of hydrogen gas if calcium metal reacts with water at standard temperatur
12345 [234]

Answer:

The mass of water is 18 g

Explanation:

The reaction of calcium with water can be represented in the equation below:

Ca + 2H₂O --------->Ca(OH)₂ +H₂

1 Mole of gas at STP = 22.4L

From the displacement reaction above, calculate the mass of water that will produce 22.4L of hydrogen gas at STP.

Mass of 2H₂O = 2(2x1 + 16) = 2X18 = 36 g/mol

Using proportional analysis;

36 g of 2H₂O produced 22.4 L of H₂, then

what mass of 2H₂O will produce 11.2L of  H₂ ?

Mathematically,

22.4 L ----------------------------------> 36g

11.2 L -----------------------------------> ?

Cross and multiply, to obtain the expression below

= (11.2 X 36)/22.4

= 18 g

Therefore, the mass of water is 18 g

5 0
3 years ago
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