Question

The mass defect for the formation of lithium-6 is 0.0343 g/mol. The binding energy for lithium-6 nuclei is ________ kJ/mol. Enter your answer in exponential format (sample 1.23E-4) with two decimal places and no units.

Answer 1

Answer: The binding energy for lithium-6 nuclei is 3.09 E+11

Explanation:

Binding energy is defined as the energy which holds the nucleus together. It is basically the product of mass defect and the square of the speed of light.

This energy is calculated by using Einstein's equation, which is:

$E=\Delta mc^2$

where,

E = Binding energy of the atom

$Delta m$ = Mass defect = 0.0343g/mol = $0.0343\times 10^{-3}kg/mol$     (Conversion factor: $1kg=10^3g$ )

c = speed of light = $3\times 10^8m/s$

Putting values in above equation, we get:

$E=0.0343\times 10^{-3}kg/mol\times (3\times 10^8m/s)^2$

$E=3.09\times 10^{14}J/mol=3.09\times 10^{11}kJ/mol$     (Conversion factor: $1kJ=10^3J$ )

Hence, the binding energy for lithium-6 nuclei is 3.09 E+11