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Svet_ta [14]
2 years ago
7

What type of mirror could have resulted in the image of the giraffe above?

Chemistry
1 answer:
natka813 [3]2 years ago
8 0

Answer:

A convex mirror

Explanation:

Good luck on the test m8!

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3 years ago
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A reaction was suppose to produce 20 L of gas. Only 12 litters of gas were produced in the lab. What is the percent yield for th
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Answer:

\boxed {\boxed {\sf 60 \%}}

Explanation:

Percent yield is a ratio of the actual yield to the theoretical yield. It is found using this formula:

\% \ yield= \frac {actual \ yield}{theoretical \  yield} *100

The actual yield is 12 liters, because that was actually produced in the lab.

The theoretical yield is 20 liters, because that was the expected yield.

\% \ yield= \frac {12 \ L}{20\ L} *100

\% \ yield= 0.6*100

\% \ yield= 60

For this reaction, the percent yield is 60%.

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2 years ago
The electron configuration of an element is 1s2 2s2 2p1. How many valance electrons does the element have. 1,2,3 or 4
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3

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G determine the concentration of an hbr solution if a 45.00 ml aliquot of the solution yields 0.6485 g agbr when added to a solu
Sunny_sXe [5.5K]

The molecular weight of silver bromide (AgBr) is 187.77 g/mole. The presence of the ions in solution can be shown as- AgBr (insoluble) ⇄Ag^{+} + Br^{-1}.

45.00 mL of the aliquot contains 0.6485 g of AgBr. Thus 1000 mL of the aliquot contains \frac{0.6485}{45}×1000 = 14.411 gm-mole. Thus the solubility product K_{sp}of AgBr = [Ag^{+}]×Br^{-}.

Or, 5.0×10^{-13} = S^{2} (the given value of solubility product of AgBr is 5.0×10^{-13} and the charge of the both ions are same).

Thus S = (5.00×10^{-13})^{1/2} = 7.071×10^{-7} g/mL.

Thus the concentration of Br^{-1} or HBr is 7.071×10^{-7} g/mL.

4 0
3 years ago
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