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Svet_ta [14]
3 years ago
7

What type of mirror could have resulted in the image of the giraffe above?

Chemistry
1 answer:
natka813 [3]3 years ago
8 0

Answer:

A convex mirror

Explanation:

Good luck on the test m8!

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What is a visual or mathematical representation of an object system or concept
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The visual or mathematical representation of an object system or concept is known as a model. Hope this helps and mark as brainliest!
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The reaction Ba(NO3)2(aq) + Na2SO4(aq) >> 2NaNO3(aq) + BaSO4(s) goes to completion because a
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Answer:

2. precipitate is formed

Explanation:

In this reaction barium nitrate and sodium sulfate solutions react to form a barium sulfate precipitate.Barium and sulfate ions will react to give barium sulfate precipitate where as the sodium and nitrate ions are spectator ions.

The net ionic equation after removing unchanged ions from each side of the full ionic equation will be;

Ba²⁺+ SO₄²⁻ →  BaSO₄ (s)

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3 years ago
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What structure is the opening that allows you to enter the eye
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A sealed vessel contains 0.200 mol of oxygen gas, 0.100 mol of nitrogen gas, and 0.200 mol of argon gas. The total pressure of t
babunello [35]

Answer:

D

Explanation:

We can use the mole ratio to calculate the partial pressure. The total number of moles is 0.2 + 0.2 + 0.1 = 0.5 moles

Now, we know that the mole fraction of the argon gas would be 0.2/0.5

The partial pressure is as follows. To calculate this, we simple multiply the number of moles by the total pressure.

0.2/0.5 * 5 = 1.0/0.5 = 2.00atm

D

8 0
3 years ago
If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?
andre [41]

Complete question:

The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.44×10⁻⁴ s⁻¹ at a certain temperature.

If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?

Answer:

After 210 s the concentration of SO2Cl2  will be 0.121 M

Explanation:

ln\frac{[A_t]}{[A_0]} =-kt

where;

At is the concentration of A at a time t

A₀ is the initial concentration of A

k is rate constant = 1.44×10⁻⁴ s⁻¹

t is time

ln(At/A₀) = -( 1.44×10⁻⁴)t

ln(At/0.125) =  -( 1.44×10⁻⁴)210

ln(At/0.125) = -0.03024

\frac{A_t}{0.125} = e^{-0.03024

At/0.125 = 0.9702

At = 0.125*0.9702

At = 0.121 M

Therefore, after 210 s the concentration of SO2Cl2  will be 0.121 M

6 0
3 years ago
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