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Ganezh [65]
3 years ago
5

In the reaction MgCl2 + 2KOH Mg(OH)2 + 2KCl, if 3 moles MgCl2 are added to 4 moles KOH, what determines how much Mg(OH)2 is made

?
A. The amount of MgCl2 + KOH
B. The amount of KCl
C. The amount of MgCl2
D. The amount of KOH
Chemistry
1 answer:
LenKa [72]3 years ago
8 0
The correct option is C. The amount of MgCl2. we know this because <span>no matter how much you increase KOH, if you dont increase Mgcl2, the amount of Mg(OH)2 remains the same. Hope this works for you</span>
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