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2 years ago

If a plant produces 8.46 mol C6H12O6, how many moles of H2O are needed?

Chemistry

1 answer:

Ierofanga [76]2 years ago

8 0

Answer:

50.76 mol H2O.

Explanation:

The photosynthesis follows the equation:

6CO2 + 6H2O ---> C6H12O6 + 6O2

This means that 6 mol of H2O are needed to obtain 1 mol of C6H12O6 (see the numbers that precedes every molecule to know how many mols are in game).

So we can say that:

1 mol C6H12O6 --------- 6 mol H2O

8.46 mol C6H12O6 -----x= 8.46 x 6 : 1 = 50.76 mol H20

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Which is a balanced chemical equation?

Degger [83]

<h3>Answer:</h3>

B. C7H16 + 11O2 → 7CO2 + 8H2O

<h3>Explanation:</h3>

In a balanced chemical equation, the number of atoms of each element is equal on both sides of the equation.

In this case, the balanced chemical equation is;

C7H16 + 11O2 → 7CO2 + 8H2O

Because, it has 7 carbon atoms, 16 hydrogen atoms and 22 oxygen atoms on each side of the equation.

When an equation is balanced it obeys the law of conservation of mass such that the mass of reactants will be equal to the mass of products.

8 0

2 years ago

You decide you want to carry a boulder home from the beach. It is 20 centimeters on each

e-lub [12.9K]

Answer:

Weight of boulder = 22,400 gram

Explanation:

Given:

Volume = 8,000 cm³

Density = 2.8

Find:

Weight of boulder

Computation:

Weight of boulder = Volume x Density

Weight of boulder = 8,000 x 2.8

Weight of boulder = 22,400 gram

3 0

3 years ago

When .080 moles of propane burn at STP, what volume of carbon dioxide is produced?

ahrayia [7]

Taking into account the reaction stoichiometry and the definition of STP, 5.4 L of carbon dioxide is produced.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

C₃H₈: 1 mole
O₂: 5 moles
CO₂: 3 moles
H₂O: 4 moles

<h3>Moles of CO₂ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 1 mole of C₃H₈ form 3 moles of CO₂, 0.080 moles of C₃H₈ form how many moles of CO₂?

$amount of moles of CO_{2} =\frac{0.080 moles of C_{3} H_{8}x3 moles of CO_{2} }{1 mole of C_{3} H_{8} }$

<u><em>amount of moles of CO₂= 0.24 moles</em></u>

<h3>Definition of STP condition</h3>

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

<h3>Volume of CO₂ produced</h3>

You can apply the following rule of three: If by definition of STP 1 mole of CO₂ occupies 22.4 L, 0.24 moles of CO₂ how much volume does it occupy?

$volume of CO_{2} =\frac{0.24 molesx22.4 L}{1 mole}$