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dangina [55]
2 years ago
11

Name one other organ system that would be affected if it had no marrow.Explain?

Chemistry
1 answer:
muminat2 years ago
6 0
It can possible be you're arteries or also you're intestines with is large and small.

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Forensic toxicology involves not only the area of toxicology, but also the use of areas such as analytic chemistry and pharmacol
grandymaker [24]

Answer:

The answer is True

Explanation:

Forensic toxicology involves or  employs or uses disciplines such as analytical chemistry, pharmacology and clinical chemistry to aid medical or legal investigation.

3 0
3 years ago
Read 2 more answers
294 g of potassium dichromate contains 52 g of chromium and 39 g of potassium. What is the mass percent of oxygen in the compoun
IgorLugansk [536]
69.047% is the answer to this question
3 0
2 years ago
Read 2 more answers
How many protons and electrons are present in Au+?
balandron [24]

Answer:

Protons: 79

Electrons: 78

Explanation:

1. The number of protons is the atomic number (The atomic number for Au on the periodic table is 79)

2. Since the charge is +1 (positive) it means that there's one more proton than electrons. So, 79-1 = 78 electrons

7 0
3 years ago
Consider the following reaction between calcium oxide and carbon dioxide: CaO(s)+CO2(g)→CaCO3(s) A chemist allows 14.4 g of CaO
sweet-ann [11.9K]

Answer:

Theoretical yield =26.03 g

Percent yield = 87%

Limiting reactant = CaO

Explanation:

Given data:

Mass of CaO = 14.4 g

Mass of CO₂ = 13.8 g

Actual yield of CaCO₃ = 22.6 g

Theoretical yield = ?

Percent yield = ?

Limiting reactant = ?

Solution:

Chemical equation:

CaO + CO₂   → CaCO₃

Number of moles of CaO:

Number of moles  = Mass /molar mass

Number of moles = 14.4 g / 56.1 g/mol

Number of moles  = 0.26 mol

Number of moles of CO₂:

Number of moles = Mass /molar mass

Number of moles = 13.8 g / 44 g/mol

Number of moles = 0.31 mol

Now we will compare the moles of CO₂ and CaO with CaCO₃ .

                  CO₂         :                CaCO₃  

                  1               :                 1

                 0.31           :              0.31

                CaO           :               CaCO₃  

                 1                :                 1

                 0.26         :              0.26

The number of moles of  CaCO₃ produced by CaO are less it will be limiting reactant.

Mass of CaCO₃: Theoretical yield

Mass of CaCO₃ = moles × molar mass

Mass of CaCO₃ =0.26 mol × 100.1 g/mol

Mass of CaCO₃ =  26.03 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 22.6 g/ 26.03 g × 100

Percent yield = 0.87× 100

Percent yield = 87%

Limiting reactant:

The number of moles of  CaCO₃ produced by CaO are less it will be limiting reactant.

7 0
3 years ago
Bas +<br> PtF2 →<br> BaF2 +<br> Pts<br> Need to balance it
Basile [38]

it is already balanced

REACTANTS

Barium sulfide (BaS) + platinum (Ii) fluoride

PRODUCT

Barium fluoride (BaF2) + Cooperite (PtS)

Hope this answer helps you dear! take care

5 0
2 years ago
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